3.70. What is the turning action of the forces shown about the diagonal A-D?
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- ENTER YOUR ANSWER THE WAY I SPECIFY HERE IN ADDITION TO DOING IT ON SCRATCH PAPER Copyright © McGraw-Hill Education. Permission required for reproduction or display. -3.6 m A 2400 N 2.7 m D 2.7 m F E -4.8 m a. Determine the vertical component Cy and its direction at C (use "up" or "down"); enter your answer as a whole number. b. Determine the vertical component Ay and its direction at A (use "up" or "down"); enter your answer as a whole number. Example If Cy=300.5 N in the positive direction and if Ay=200.3 N in the negative direction, enter 301up;200down in that order. B C4.15. Calculate I,, ly, Iy for the section of Figure P4.9 above. You can use the results from Example B.1.Draw a line AB of length 120 mm and by construction obtain a point P dividing AB internally in the ratio (a) 3:5 (b) 4:7. Measure AP (to the nearest half mm).
- The following diagram corresponds to questions 1 to 3. A beam rests on two sharp edges as shown on the image. The beam has a length of 7,50 m and a mass of 4,25 kg. Object 1 has a mass of 1,50 kg; object 2 has a mass of 2,35 kg. Point P is 0,50 m form the center of the beam. d 2 Pl CG 1. How much is the torque done by object 1 around point P? A. 55,2 N*m B. 7,36 N*m С. 62,5 N*m D. Object 1 doesn't exert a torque.Figure (a) shows the cross section of a column that uses a structural shape known as W867 (wide-flange beam, nominally 8 in. deep, weighing 67 lb/ft). The American Institute of Steel Construction Structural Steel Handbook lists the following cross-sectional properties: A=19.7in.2,Ix=272in.4, and Iy=88.6in.4. Determine the dimensions of the rectangle in Fig. (b) that has the same Ix and Iy as a W867 section.Compare the magnitudes of the equilibrant vectors measured from the experiment with those obtained from the graphical and component methods. Example: A: 200 g 60° above +x axis B: 300 g 45° above -x axis C: 400 g 30°below -x-axis A, A cos a = 1.96 N x cos 60° = 0.98 N B₂B cos b = 2.94 N x cos 135º = -2.08 N C, C cos g = 3.92 N x cos 210°= -3.39 N R₂-A, + B + C₂ = -4.49 N A, A sin a = 1.96 N x sin 60° = 1.70 N By B sin b = 2.94 N x sin 135º = 2.08 N C, C sin g = 3.92 N x sin 210° = -1.96 N Ry= Ay+ By + Cy = 1.82 N Questions: I: (a) A: 200 g along +x axis B: 100 g 45° above -x axis A₂ = A cos a = B₂ =B cos b = R₂-A₂+ B₁₂= A₂ = A sin a = B, = B sin b = R₂ = A + B₂ = R=(R₂. R₂):_ Quadrant R = √ (R₂²+R₂²) = Direction:q=tan [R, /R.] (c) A: 100 g along -y axis B: 200 g along -x axis A = A cos a = B = B cos b = R₂-A₂+ B₂ = A = A sin a = B, B sin b = R=A, +B₂ = R=(R₁, R₂): Quadrant R = √ (R₂²+R₂²) = Direction:q tan¹ [R, /R]
- The following diagram corresponds to questions 1 to 3. A beam rests on two sharp edges as shown on the image. The beam has a length of 7,50 m and a mass of 4,25 kg. Object 1 has a mass of 1,50 kg; object 2 has a mass of 2,35 kg. Point P is 0,50 m form the center of the beam. CG 1. How much is the torque done by object 1 around point P? A. 55,2 N*m B. 7,36 N*m C. 62,5 N*m D. Object 1 doesn't exert a torque. 2. How much is the torque done by the force of gravity of the beam around point P? A. 20,8 N*m N-m ך177 .B C. 156 N*m D. 313 N*m 3. If you needed to cancel the nomal forces of the two objects, where you should place object 2? The axis of rotation is point P. A. 3,30 m from point B. 9,18 m from point P C. 5,69 m from point P D. 3,62 m from point P10 / 36 110% Q22](problem 2/28: p37) (¿ãt2) Determine the resultant `R" of the two forces Shown in fiqure, and find the angle o" between R and A- 10 800 N the x-axis . 900 N 25 4" Ane R=10379 N . 0 =66-8 Q23]( problem 2/25 's p37) Exemple201-2o At What angle x must the Type here to search2:56 90 0t O 22 classroom.google.com/u/ 8 ميكانيك هندسي sOi Jbls ara A prybar in used to remove a nail an shown. De termine the moment of the 240-N foree about the point O of contact between the prybar and the small support block P30N 16m 240 N 350 mm PROBLEM 3/s a A man esertaa farce Fon the handle of the stationary wheelbarruw at A. The weight of the wheelburrow along with ita load of dirt is t85 Ib with center of gravity at G. For the eonfiguration shown, what fore F muat the man apply at A to make the net moment about the tire contact pint equal to er 30 mm PROBLEM 2/33 Representative Problems 34 An everhead view of a door ia shwwn. If the com presnive foree F acting in the ceupler arm of the hy draulic door closer ia 17 Ih with the orientation ahown, determine the mement of this force about the hinge axis O PROBLEM 2/36 aT A 150-N pul Tin applied te a cord, which is wound ecurely around the inner hub of the drum Determine the moment ef T about the drum eenter C. At what angle e…
- Q. 2 Find the pasition of centraid with respect to given X and Y akis af shaded portian in the following figure: 225Q3: Draw the geometry shown in figure below. 38 88 12p 56 -2812 50Show conv D +z axis 01) Given the figure, AB=5m, BC= 8m and AG= 7m and pt 0 is origin. Determine the following: 250 N B *y axis 1) What is magnitude of R and Cr in pt G? 20 kN m 1689 Ibt (Unit must be in N and kN-m) 1269 pounds 2) What is the magnitude of R and Cr in pt 0? +x axis (Unit must be in N and kN-m) 3) Unit Vector of R in the system. 4) Direct Cosines of Cr in pt 0.