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3. The torque due to a force Facting at a displacement from the axis of rotation is given by +=xF. The force is at oriented 110⁰ cow from +x and is oriented at 60° from +x. Determine the magnitude and direction of the torque. 20N VL L... 3m 4. The cross product can also be determined if we know the components of the two vectors involved. The easiest way to do this is to write the cross product the determinant of a 3x3 matrix. The first row of the matrix is the unit vectors, and . The 2nd row is the components of the first vector and the 3rd row is the components of the second vector. The determinant of the 3x3 matrix can be written in terms of determinants of 2x2 matrices: Ax8= A₂ Ay A₂ =¹^ *-* **** * f +k Ax Ayl By By By By B₂ The determinant of a 2x2 matrix is the product of the diagonal terms minus the product of the off-diagonal terms. Therefore b. What is the magnitude of the torque? Ax8 = {(Ay 8z - Az8y) — ¡(AxB± − A±Bx) + Â(Ax By - AyBx) a. Let 7 = (2-3k) m and F = (5î-4ƒ- 10k)N. Determine the torque in component vector form. Don't forget to include units.

3. The torque due to a force Facting at a displacement from the axis of rotation is given by +=xF. The force is at oriented 110⁰ cow from +x and is oriented at 60° from +x. Determine the magnitude and direction of the torque. 20N VL L... 3m 4. The cross product can also be determined if we know the components of the two vectors involved. The easiest way to do this is to write the cross product the determinant of a 3x3 matrix. The first row of the matrix is the unit vectors, and . The 2nd row is the components of the first vector and the 3rd row is the components of the second vector. The determinant of the 3x3 matrix can be written in terms of determinants of 2x2 matrices: Ax8= A₂ Ay A₂ =¹^ *-* **** * f +k Ax Ayl By By By By B₂ The determinant of a 2x2 matrix is the product of the diagonal terms minus the product of the off-diagonal terms. Therefore b. What is the magnitude of the torque? Ax8 = {(Ay 8z - Az8y) — ¡(AxB± − A±Bx) + Â(Ax By - AyBx) a. Let 7 = (2-3k) m and F = (5î-4ƒ- 10k)N. Determine the torque in component vector form. Don't forget to include units.

Physics for Scientists and Engineers, Technology Update (No access codes included)
Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter10: Rotation Of A Rigid Object About A Fixed Axis
Section: Chapter Questions
Problem 10.3OQ: A wheel is rotating about a fixed axis with constant angular acceleration 3 rad/s2. At different...
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3. The torque due to a force Facting at a displacement from the axis of rotation is given by +=xF. The force is at oriented 110⁰ cow from +x and is oriented at 60° from +x. Determine the magnitude and direction of the torque. 20N VL L... 3m 4. The cross product can also be determined if we know the components of the two vectors involved. The easiest way to do this is to write the cross product the determinant of a 3x3 matrix. The first row of the matrix is the unit vectors, and . The 2nd row is the components of the first vector and the 3rd row is the components of the second vector. The determinant of the 3x3 matrix can be written in terms of determinants of 2x2 matrices: Ax8= A₂ Ay A₂ = ³^ 4-√2 4+** * f +k Ax Ayl By By By By B₂ The determinant of a 2x2 matrix is the product of the diagonal terms minus the product of the off-diagonal terms. Therefore b. What is the magnitude of the torque? Ax8 = {(Ay 8z - Az8y) — ¡(AxB± − A±Bx) + Â(Ax By - AyBx) a. Let 7 = (2-3k) m and F = (5î-4ƒ- 10k)N. Determine the torque in component vector form. Don't forget to include units.
Transcribed Image Text:3. The torque due to a force Facting at a displacement from the axis of rotation is given by +=xF. The force is at oriented 110⁰ cow from +x and is oriented at 60° from +x. Determine the magnitude and direction of the torque. 20N VL L... 3m 4. The cross product can also be determined if we know the components of the two vectors involved. The easiest way to do this is to write the cross product the determinant of a 3x3 matrix. The first row of the matrix is the unit vectors, and . The 2nd row is the components of the first vector and the 3rd row is the components of the second vector. The determinant of the 3x3 matrix can be written in terms of determinants of 2x2 matrices: Ax8= A₂ Ay A₂ = ³^ 4-√2 4+** * f +k Ax Ayl By By By By B₂ The determinant of a 2x2 matrix is the product of the diagonal terms minus the product of the off-diagonal terms. Therefore b. What is the magnitude of the torque? Ax8 = {(Ay 8z - Az8y) — ¡(AxB± − A±Bx) + Â(Ax By - AyBx) a. Let 7 = (2-3k) m and F = (5î-4ƒ- 10k)N. Determine the torque in component vector form. Don't forget to include units.
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