3. Draw the structure of the catalytic triad found in the active site of chymotrypsin and explain how this arrangement of functional groups activates the nucleophilic serine side chain.
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- 5. Gout can be caused by superactivation of PRPP synthase, or partial deficiency of hypoxanthine-guanine phosphoribosyl transferase. Why the change in these enzyme activities can induce the development of this disorder? For the answer: a) write down the scheme of the reactions catalyzed by these enzymes;b) specify metabolic pathways these reactions take part in; c) answer the main question of the problem.2. Consider the enzymatic reaction scheme: Asparagine + H20 Aspartate + NH3: a) calculate the specific activity of the enzyme, if in 30 seconds as a result of a reaction involving 3 mg of the enzyme under optimal conditions (pH 8.0, 37 °C) 75 umol aspartate is obtaincd; b) describe the reasons for the decrease in enzyme activity after incubation for 10 minutes at 70 °C (provide an appropriate graph).1.The diagram below shows an outline of the aminotransferase mechanism that skips the specific steps that show how electrons flow when a Schiff base is formed or is hydrolyzed. Using the mechanistic details given below A. Draw the mechanism for Enzyme- PLP Schiff base formation using pyridoxal and the lysine amine group using arrow to indicate electron flow. B. Draw the mechanism for hydrolysis of the Schiff base to form the a-keto acid, which is the reverse of the first reaction. Stage 1 Lys residue 2-O,PO- Enz Amino acid Lys residue (CH2)4 (CH₂2)4 H R-C-COO R- NH₂ NH₂ R-C-COO *NH₂ H H- 2-0,PO- 2-0,PO- A. show how this forms Stage 1 Lys residue Enz (CH2)4 HO 2-O,PO Enzyme-PLP Schiff base OH Amino acid-PLP Schiff base (aldimine) LOH 2-0₂PO- OH 20,PO- a-Keto acid COO Ketimine a-Keto acid 2-0,PO- R-C- NH₂ B. show how the a-keto acid forms a-Keto acid H Enzyme-PLP Schiff base الرواية وطري Ketimine Pyridoxine (vitamin B6) Pyridoxal phosphate (PLP) Pyridoxamine phosphate Stage 2 Amino acid…
- 2. To the right is a schematic diagram of His $7 the active site in the Michaelis complex of a-chy- motrypsin and a polypeptide substrate. Describe briefly the catalytic or structural roles of the residues listed below: но — Ser 195 (а) Ser195 AA,-C-ÇH-NH-C-ÇH -NH -AAn R R H H. 193 Gly Ser195 (b) His57 (c) NH groups of Gly193 and Ser195 (d) The most favorable side chain R for binding (e) Identify the scissile bond with an arrow, i.e., the bond in the peptide substrate that is cleaved as a result of the catalytic action of the enzyme. You can point to it on the diagram above.3. Solve the sequence of an oligopeptide 7 residues long which gave: Asp Leu Lys Met Phe Tyr The following facts were observed: a. Trypsin treatment had no apparent effect b. The PTH derivative from Edman degradation was c. Brief chymotrypsin treatment yielded several products including but not limited to a dipeptide and a tetrapeptide. The amino acid composition of the tetrapeptide was Leu, Lys, and Met. d. Cyanogen bromide treatment yielded a dipeptide, a tetrapeptide, and a free Lys.3. Solve the sequence of an oligopeptide 7 residues long which gave: Asp Leu Lys Met Phe Tyr The following facts were observed: a. Trypsin treatment had no apparent effect b. The PTH derivative from Edman degradation was c. Brief chymotrypsin treatment yielded several products including but not limited to a dipeptide and a tetrapeptide. The amino acid composition of the tetrapeptide was Leu, Lys, and Met. d. Cyanogen bromide treatment yielded a dipeptide, a tetrapeptide, and a free Lys. Instructions Make use of the table below to determine the sequence of the mystery protein.
- 1. Depict the structure features in the active site of cysteine protease 2. provide a step-wise reaction mechanism to show the hydrolysis of the peptide bond catalyzed by a cysteine protease5. Shown below are the first steps in the mechanism of a cysteine protease, which catalyses amide bond hydrolysis in a similar manner as serine proteases. (a) Complete this mechanisms, and (b) sketch the approximate reaction coordinate diagram for this catalyzed reaction relative to the uncatalyzed proteolysis. HN N HN cysteine protease10. Chymotrypsin is a serine protease enzyme. The Km for the reaction of chymotrypsin with N-acetylvaline ethyl ester is 8.8*102, and the Km for the reaction of chymotrypsin with N- acetyltyrosine ethyl ester is 6.6*10“ M. catalytic triad Ser 195 His 57 Gly 193 N-H OH R-N- Ca N-H O-C- Asp 102 N-acetyl valine N-acetyl tyrosine Chymotrypsin Active Site a. What is the nucleophile here and how is it activated? b. Which substrate has an apparent higher affinity for the enzyme. c. Propose a reason for the difference in affinity based on the shape of each of the substrates (see active site figure, cleaves on the C-side of aromatic residues).
- 5. Suppose an enzyme needed a cysteine thiol (sulfhydryl) group for its catalytic activity, and catalysis required the Cys thiol to act as a nucleophile at the beginning of the catalytic cycle. That would mean the Cys residue had to be in its UNPROTONATED (conjugate base) form. If that particular Cys residue in that protein had a pKą of 7.5, what fraction (percent, or proportion) of the total enzyme molecules would have the Cys R group in its ACTIVE form at pH 7.0?1. Acid phosphatases are an important group of enzymes that can be detected in human bloodserum. Under slightly acidic conditions (pH 5.0), this group of enzymes can hydrolyzebiological phosphate esters as follows:R-O-P-O3-2 + H 2O R-OH + HO-P-O3-2.Acid phosphatases are produced and can be detected in erythrocytes, kidney, spleen, the liver,and prostrate gland. The enzyme from the prostrate gland is clinically important because anincreased activity in the blood is frequently an indication of cancer of the prostrate gland.Tartrate ion can strongly inhibit the phosphatase from the prostrate gland, but not acidphosphatases from other tissues. How can you use the information above to develop a specificprocedure for measuring the activity of the acid phosphatase of the prostrate gland in humanblood serum?7. Chalcone isomerase catalyzes the reaction illustrated below. A series of modification experiments were performed on this enzyme to identify which amino acid residues might be in the active site and which might promote the cyclization reaction. OH Ho. Но Explain the following results: A) Acetic anhydride treatment inhibited enzyme activity. B) Pyrocarbonate inhibited activity and was found to modify 7 residues. However, this enzyme only contains 6 His and modification of these did not affect activity. C) lodoacetate inhibited activity but this effect coult be decreased in the presence of substrate or product. D) Methane methanethiol sulfonate modified the enzyme but did not inhibit catalytic turnover. In addition, this modification was reversed in the presence of B-mercaptoethanol. keNyons Rengent