the2513.02.52.61.5-1.060.5yo‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒Please show here the calculation of the slope.Slope =0.00 OpFigure.32.5n/mOUL0.030.04 0.05 006 007 0.08 Figure 4. How to correctly measure the position of the bottom of the spring when theweight hanger carries the required added masses.M₁ (8) = 6₁54Msw(g)Table # 1: Determination of the spring constant Kg= 9.80 m/s²xo (cm) = 2MT= Mh+ MswMTMT(kg)6.6.5, 0.066.5116:52 0.11 6.5F =W=MrgF(N)00.65171.1417xf(cm)11.73.34.9X = Xf- XoX(cm)X(m)050100150200166.5 0.766.5 1.63/7216.30.2165 2.1217266.55 (2.2665 2.6/17Average force constant Kavg2508Force constant Ktren from the slope of the trendline in the graph% relative difference between Kavg and KtrenMh: Mass of the weight hangerMsw: Mass of added slotted weightsMr: Total MassW: Weight of hanger plus slotted weightsK =F(N)x(m)K(N/m)0.20.165√72.5ch 0.025 45:068You 0.09 40,79250:055 38 576363647.2 0.072 36.973 6 UI!5535.7829 n/mXo: Position of the spring's bottom (unstretched)xf: Position of the spring's bottom (stretched)x: Elongation of the springK: Force constant of the spring252.0.0.C

Name: the2513.02.52.61.5-1.060.5yo‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒Please show here the
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Description: the2513.02.52.61.5-1.060.5yo‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒Please show here the calculation of the slope.Slope =0.00 OpFigure.32.5n/mOUL0.030.04 0.05 006 007 0.08 Figure 4. How to correctly measure the position of the bottom of the spring when theweight hanger

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200 216.2 0.2165 2.1271 250 8 266.55 02. 266.5 2.6/17 Average force constant Kaug Force constant Ktren from the slope of the trendline in the graph % relative difference between Kavg and Ktren Mhi Mass of the weight hanger 1. Xo: Position

200 216.2 0.2165 2.1271 250 8 266.55 02. 266.5 2.6/17 Average force constant Kaug Force constant Ktren from the slope of the trendline in the graph % relative difference between Kavg and Ktren Mhi Mass of the weight hanger 1. Xo: Position

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter24: Electromagnetic Waves

Section: Chapter Questions

Problem 2PE: Show that, when SI units for 0 and 0 are entered, the units given by the right-hand side of the...

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