2. An enzyme that causes an apple to turn brown after it is cut was studied using Lineweaver-Burke kinetics and the data below was obtained [S] Vi enzyme Sample 11 4.8mM 0.081 1 Sample 2 1.2 mM 0 048 Sample 3 0.6 mM 0.035 Using graphing software like excel or a graphing calculator calculate the V max and Km for this Sample 4 0.3 mm 0.02

2. An enzyme that causes an apple to turn brown after it is cut was studied using Lineweaver-Burke kinetics and the data below was obtained [S] Vi enzyme Sample 11 4.8mM 0.081 1 Sample 2 1.2 mM 0 048 Sample 3 0.6 mM 0.035 Using graphing software like excel or a graphing calculator calculate the V max and Km for this Sample 4 0.3 mm 0.02

Chemical Principles in the Laboratory

11th Edition

ISBN:9781305264434

Author:Emil Slowinski, Wayne C. Wolsey, Robert Rossi

Publisher:Emil Slowinski, Wayne C. Wolsey, Robert Rossi

Chapter21: Rates Of Chemical Reactions, Ii. A Clock Reaction

Section: Chapter Questions

Problem 2ASA

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Sol. No. 1 2 3 4 5 Volume of KI (ml) 20 18 15 12 10 [KI] K 0.195121951 0.00039 0.175609756 0.0004 0.146341463 0.0005 0.117073171 0.0006 0.097560976 0.0004 Log K Q1) Plot Log K' on y-axis and Log [KI] on x-axis A) Slope = B) Intercept = e) Log K = D) K = Log [KI] -3.40894 -0.70969387 -3.39794 -0.75545136 -3.30103 -0.834632606 -3.22185 -0.931542619 -3.39794 -1.010723865
What are the units for each parameter? maximum velocity Michaelis-Menton constant catalytic efficiency catalytic constant 111 M/S M 1/(Ms) 1/s M/s 100/(Ms)
AvapH dT T(V – Vi) dP AvapH_ AvapH _ AvapH -P TVg RT RT2 - Rewrite this equation after separating the variables P and T.
Using the kinetic data pictured, estimate Vmax and Km for the catalysis of Substrate 1 by the following enzyme (using the correct units).
. Derive an equation expressing v/Vmax \1-v/Vmax. as a function of log[S] for an enzyme that obeys the Michaelis-Menten equation. For an allosteric enzyme, show how you could use this equation to obtain K and K (the KM values for T and R states) from a Hill plot of kinetic data
In chemistry class, a student conducted an investigation about factors affecting the solubility of copper (II) sulfate (CUSO4) in water. The data was recorded in the table below. Trial Factors Compound not stirred Temperature: 60ºC Large crystals Compound was stirred 2 Temperature: 25ºC Large crystals Compound was not stirred 3 Temperature 25°C Large crystals Compound was stirred 4 Temperature 60ºC Finely crushed powder Which trial will have the slowest rate of dissolving? Explain the reasoning for your answer.
The image below shows a Lineweaver-Be plot for an Enzyme catalysed reaction. Units for the Y-axis is (s/mmol) and X-axis is (1/mM). Use the data on the plot to calculate Vmax and Km for this reaction. -0.2 0.20 0.15 0.10 0.05 0.00 0.0 ENZYME CATALYSED REACTION 0.2 0.4 O Vmax = -0.089 mmol/s; Km = 0.0145 mM O Vmax = 0.0145 s/mmol; Km = -0.089 1/mM Vmax = 68.97 mmol/s; Km = 11.24 mM O Vmax = 11.24 mM; Km = 68.97 mmol/s 0.6 y = 0.1624x + 0.0145 R² = 0.9967 0.8 1.0 1.2
Using the data provided use a Michaelis-Menten and Lineweaver-Burk plot to determine the K and Vmax values for enzyme. [9], mM 3.0 4.58 5.0 6.40 7.0 7.72 9.0 8.72 11.0 9.50 [S], mM V, no Inhibitor (Arbitary units) 1 x 10-4 0.026 5 x 10-4 0.092 1.5 x 10-³ 0.136 2.5 x 10-³ 0.150 0.165 5 x 10-3
hello, i sent this question before but the answer you rpovided for both wasnt right and i couldnt undertstand how you got the answer. can you please show me a handwritten solution for better understanding. 1a) The decomposition of ethanol at some constant temperature (above 500°C), over a copper surface, C2H5OH(g) CH3CHO(g) + H2(g) was studied by monitoring the total pressure with time.The following data were obtained: t (s) Ptotal (torr) 0 120 45 131 139 154 233 177 376 212 380 213 What will be the total pressure at t = 462 s? 1b) What is the rate constant (k)?(Include appropriate units.)
er 11 X 4-7) now-owl.cengagenow.com/ilrn/takeAssignment/ta... t t t ot ot OWLv2 | OX ot OWLv2 | A X + OWLv2 | Assignmen... Labflow - Course: U... M Inbox (2,487) [References] Chemists commonly use a rule of thumb that an increase of 10 K in temperature doubles the rate of a reaction. What must the activation energy be for this statement to be true for a temperature increase from 41 to 51°C? Activation energy = kJ/mol Submit Answer 6 item attempts remaining Try Another Version Previous Next x 9:03 PM 9/29/2022 S >>>
The active form of the enzyme alcohol dehydrogenase exists as a homotetramer (MW = 150 kDa), and has one identical active site located on each of its four subunits. You have performed a series of enzyme kinetic experiments using 0.025 mL of an enzyme sample that is 4.0 pg/mL and determined that the following Vmax = 2.442 x 10-2umoles/min What is the turnover number of this enzyme (in units of #/sec)? 76/ sec 305 / sec 152 / sec 4579/ sec 1526 / sec O O O O
The initial velocity catalyzed by Enzyme A (red) and Enzyme B (gray) for the same substrate is plotted below as a double reciprocal plot. For the following data - answer each of the fill-in-the-blank questions. -0.75 1/Vo (min/mm) 0.5+ 0.4+ 0.3 0.2- 0.1 -0.25 0.5 A 1.0 + 1/[S] (1/mM)