2. A M= 4942 kg rock Determine the ratio R=KE/DE of the kinetic energy K.E is released from rest at height H=50M. = MV ²/2 and gravitational energy PE =4 = mgh at height my h = 36M: al 0,861 6) 0.763 c) 0.60860 0.389 e)None
2. A M= 4942 kg rock Determine the ratio R=KE/DE of the kinetic energy K.E is released from rest at height H=50M. = MV ²/2 and gravitational energy PE =4 = mgh at height my h = 36M: al 0,861 6) 0.763 c) 0.60860 0.389 e)None
Modern Physics
3rd Edition
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Chapter2: Relativity Ii
Section: Chapter Questions
Problem 17P
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