10. In an experiment to determine the specific heat capacity of a certain metal, a student obtained the values given below; Mass of water Mw = 44.3g Mass of calorimeter, Mc = 58.7g Initial temperature of water before boiling, T₂= 18.4 °C Final temperature reached by the heated water, T₁= 85.4 °C Final temperature reached by the mixture (water+ calorimeter+ specimen metal), TF = 20.2 °C Calculate the specific heat capacity, C₁ of the specimen metal using the equation; C₁= {[(MwCw+ McCc) (TF-T₂)] / M₁(T1-TF)} Where; specific heat capacity of water, Cw=4186J/Kg K - specific heat capacity of the calorimeter, Cc= 386J/Kg K

College Physics
10th Edition
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter11: Energy In Thermal Processes
Section: Chapter Questions
Problem 15P: What mass of water at 25.0C must be allowed to conic to thermal equilibrium with a 1.85-kg cube of...
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10. In an experiment to determine the specific heat capacity of a certain metal, a student obtained
the values given below;
Mass of water Mw = 44.3g
Mass of calorimeter, Mc = 58.7g
Initial temperature of water before boiling, T₂= 18.4 °C
Final temperature reached by the heated water, T₁= 85.4 °C
Final temperature reached by the mixture (water+ calorimeter+ specimen metal), TF = 20.2 °C
Calculate the specific heat capacity, C₁ of the specimen metal using the equation;
C₁= {[(MwCw+McCc) (TF-T2)] / M1(T1-TF)}
Where; specific heat capacity of water, Cw=4186J/Kg K
-
specific heat capacity of the calorimeter, Cc= 386J/Kg K
Mass of the specimen, M₁ = 17.4g
Transcribed Image Text:10. In an experiment to determine the specific heat capacity of a certain metal, a student obtained the values given below; Mass of water Mw = 44.3g Mass of calorimeter, Mc = 58.7g Initial temperature of water before boiling, T₂= 18.4 °C Final temperature reached by the heated water, T₁= 85.4 °C Final temperature reached by the mixture (water+ calorimeter+ specimen metal), TF = 20.2 °C Calculate the specific heat capacity, C₁ of the specimen metal using the equation; C₁= {[(MwCw+McCc) (TF-T2)] / M1(T1-TF)} Where; specific heat capacity of water, Cw=4186J/Kg K - specific heat capacity of the calorimeter, Cc= 386J/Kg K Mass of the specimen, M₁ = 17.4g
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