I'm having trouble finding the velocity and the kinetic energy of this problem. The answers are supposed to be v=1.31m/s and K=4.38J but I am not sure how to get those answers? system moving after box m2 drops by 0.86m? Solve this using thework and energy equation.no frictionm210. For the Atwood's machine shown. Initially mass m2 is movingupward with initial velocity 0.74 m/s. Solve this using the work and energy equation.a) How fast is the system moving just before mass m2 hits the ground h = 0.34 m below itsstarting point? (Note: it goes up, then back down again. Assume neither mass hits the pulley;assume mi does not hit the ground.)b) What is the kinetic energy of the system just before mass m2 hits the ground?%3Dm, = 2.1 kg%3Dm2 = 3.0 kg

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Answered: 10. For the Atwood's machine shown.…

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter6: Momentum And Collisions

Section: Chapter Questions

Problem 7WUE

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I'm having trouble finding the velocity and the kinetic energy of this problem. The answers are supposed to be v=1.31m/s and K=4.38J but I am not sure how to get those answers?

system moving after box m2 drops by 0.86m? Solve this using the
work and energy equation.
no friction
m2
10. For the Atwood's machine shown. Initially mass m2 is moving
upward with initial velocity 0.74 m/s. Solve this using the work and energy equation.
a) How fast is the system moving just before mass m2 hits the ground h = 0.34 m below its
starting point? (Note: it goes up, then back down again. Assume neither mass hits the pulley;
assume mi does not hit the ground.)
b) What is the kinetic energy of the system just before mass m2 hits the ground?
%3D
m, = 2.1 kg
%3D
m2 = 3.0 kg

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