1. The position , x in m of an object that move a straight line as a following relation X= 12t + 4t2 +4t³ Find that a) The average acceleration at time t=0, t= 2 s. b) The instantaneous velocity at time t=6 s.

1. The position , x in m of an object that move a straight line as a following relation X= 12t + 4t2 +4t³ Find that a) The average acceleration at time t=0, t= 2 s. b) The instantaneous velocity at time t=6 s.

Name: 1. The position , x in m of an object that move a straight line as a
Uploaded: 2024-03-05T11:56:34.000Z
Channel: Bartleby
Description: 1. The position , x in m of an object that move a straight line as a following relationX= 12t + 4t2 +4t³Find thata) The average acceleration at time t=0, t=2 s.b) The instantaneous velocity at time t=6 s.

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter2: Motion In One Dimension

Section: Chapter Questions

Problem 2.6P: The position of a particle moving along the x axis varies in time according to the expression x =...

See similar textbooks

Similar questions

A hiker walks 3.00 km north and then 4.00 km west, all in one hour and forty minutes, (a) Calculate his average speed in km/h. (b) Calculate the magnitude of his average velocity. (See Section 3.2 and 3.3.)
2. An object moves along the x-axis with its position measured relative to the origin so that its acceleration at anytime t > 0 is 4 m/s² . The initial velocity is -50 m/s. a. Determine the instantaneous velocity at anytime t. b. What is its velocity after 10 seconds? 15 seconds? b) - 10 m/s ; 10 m/s 10 m/s ANS: a) v(t) = 4t – 50
3. Shown below is the acceleration function for a particle over the approximately first two seconds of its motion. Draw an approximate graph of velocity as a function of time assuming v, = 0 m/s. alt) t 20 15 10 5. 0.5 1.0 1.5 2.0 2.5 4. Let vector A point from the origin into the first quadrant of the xy plane and vector B point from the origin into the third quadrant. The vector Ă – B must be in which quadrant?
1. The instantaneous position of a particle atong the x-axis is given by: + (1.54) t3; x in meters and t in seconds. Determine a. the average velocity during the time intervalt = 3.00 s tot = 5.00 s b. the instantaneous velocity at t = 3.00 s c. the instantaneous velocity at t = 6.00 s d. the average acceleration during the time interval t = 3.00 s tot = 5.00 e. the instantaneous acceleration att = 2.00 s %3D
2. A particle moves along the x-axis according to the equation X = 5.00 + 7.00t – 2.00t2, where x is in meters and t is in seconds. (a) What is the particle's position along the x-axis at t= 3.00-s? (b) What is the particle's average velocity between t = 0 and t= 3.00-s? (c) At what time is the particle's average velocity zero (other than at t-0)? (d) What is the particle's average acceleration between t = 0 and t = 3.00-s? (e) What is the particle's instantaneous velocity at t = 3.00-s? Answers: (a) 8.00 m (b) 1.00 m/s (c) 3.50 s (d) -4.00 m/s² (e) -5.00 m/s
5. An object has velocity vo (t) = 3i + 1j m/s at time t = 0.00 s. The acceleration of the object is alt) = 2tî+ 1t2 f m/s². If the object is located at ro (t) = 11-1jm at time %3! t = 0.00 s, what is the position of the object at time t = 1.00 s?
5. The acceleration of a jeepney is given by az (t) = at – Bt? a = 1.50 m/3 and ß = 0.120m/4 , where The motorcycle is at rest at the origin when time t = 0. %3D a. Find its position and velocity as functions of time. b. Calculate the maximum velocity it attains.
2. a) A motorcyclist who is moving along an x axis directed toward the east has a velocity given by v = (14t - 6t) m/s. If the motorcyclist starts at x = 0 at time t = 0, i) Find the time t when cyclist is again at x =0. %3D ii) What is cyclist acceleration at that time?
b. A velocity-time graph for an object moving along the x-axis is shown in the Figur e below. Determine the average acceleration of the object in the time intervalst = 5.00s to t =15.0s and t = 0 tot = 20.0s V«(m/s) 8. 6 4 -((s) 20 15 -2 -4 -6 -8
4. A box sliding down a ramp has a position ofr = (0.25t³)£ + (5t²)ŷ in meters, where t is in seconds. Find the magnitude and acceleration of the box when t = 2 s.
1. UST Eco-Tiger vehicle climbed to a hill which is defined by the equation, x2 = 625(16 –- y). If the vehicle moves from point A with a speed of 20 m/s and starts to speed up at constant rate for exactly 4.72136 seconds until it reaches point B. Determine the magnitude of the x2 = 625(16 - y) 15m vehicle's acceleration when the distance from A and B is 100 meters.
1. A particle moves in a straight line with velocity v(t) = 6t² - 18t + 12. b) Find the particles average acceleration between t = 1 sec to t = 3 sec.