. What is the heat transfer (kJ)?

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A weighted piston-cylinder device contains propane (5.3 kg) with a pressure of 1,150 kPa.  It is slowly compressed from 0.75 m3 to 0.44 m3.  During the process the temperature increases by 394 deg C. What is the heat transfer (kJ)?

 

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Expert Solution
Step 1

Given:

M=5.3 Kg

P=1.150KPa

V1=0.75 m3 to V2 =0.44 m3

The change in temperature=394 degree C

Formula used:

Q=mcpT

 

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