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Standard Deviation Essay

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For ACT
Standard deviation=17.77 For NSW

Standard deviation=18.66

For NT
Standard deviation=18.66

For QLD
Standard deviation=20.43

For VIC
Standard deviation=17.11

For WA
Standard deviation=18.47

For TAS
Standard deviation=17.45

For SA
Standard deviation=16.04

Range = largest value –smallest value
For ACT range= 155.30- 96.00 =59.3 For NSW
Range= 151.8- 96.60
= 55.20
For NT
Range= 157.60- 107.30 =50.3
For QLD
Range=153.80-86.60
=67.2
For VIC
Range=148.90-94.20
=54.7
For WA
Range=151.30-93.20
=58.1
For TAS
Range=156.70-104.50
=52.2
For SA
Standard deviation=148.90-97.50 =51.4
Calculation of coefficient of variation can be calculated using 13.764 14.139 13.335 16.573 13.743 14.712 13.292 12.968
For ACT
CV=13.764

NSW
CV=14.139 …show more content…

(a) The total no of people who has mood (affected) problems and belong to the age group of 35 to 44 are 401.7
The total no of people are 2996.2
The probability that a person, randomly selected, has mood (affected) problems and belongs to the age group 35-44= 401.7/2996.2= 0.134
(b) Total mental and behavioral problems belonging 55-64 = 460.8 Total mental and behavioral problems belonging 65-74 = 228.1 Total mental and behavioral problem belonging 75 and over = 170.4
Hence the probability that a person, randomly selected, belongs to the age group of 55 or over = (460.8+228.1+170.4)/2996.2=0.2867
(c) The person belongs to the age group of 45 to 54, the probability that he or she is suffering from alcohol and drug problems =35.9/152.1=0.236
(d) As per the given data, I calculate the incidence of various mental and behavioural problems between the two genders as follows.
Mental and behavioural problems Male % Female %
Alcohol and drug problems 64.89% …show more content…

Hence it is apparent that mental and behavioural problems on the whole are gender sensitive since the % of females affected by it is more than their natural composition in the population. Further there is variation across the various mental and behavioural problems as per gender.
Solution of Question 4.a
Determination of (meu)
Number of days when rainfall takes place = 131 days
Total number of weeks in a given year (2014) = 52 weeks
Hence the average number of raining days = 131/52 = 2.519
According to Poisson distribution Meu = 2.519
And now the probability on any given week in a year there would be no rainfall is

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