Fundamentals of General, Organic, and Biological Chemistry (8th Edition)
Fundamentals of General, Organic, and Biological Chemistry (8th Edition)
8th Edition
ISBN: 9780134015187
Author: John E. McMurry, David S. Ballantine, Carl A. Hoeger, Virginia E. Peterson
Publisher: PEARSON
bartleby

Videos

Textbook Question
Book Icon
Chapter 11, Problem 11.21UKC

Magnesium-28 decays by β emission to give aluminum-28. If yellow spheres represent 12 28 Mg atoms and blue spheres represent 13 28 Al atoms, how many half-lives have passed in the following sample?

Chapter 11, Problem 11.21UKC, Magnesium-28 decays by  emission to give aluminum-28. If yellow spheres represent 1228Mg atoms and

Expert Solution & Answer
Check Mark
Interpretation Introduction

Interpretation:

The number of half-lives when Mg-28 decays by β-emission to give Al-28 has to be calculated.

Concept Introduction:

Half-life:

The time required to reduce a radioactive isotope to half of its initial value.

Explanation of Solution

Fundamentals of General, Organic, and Biological Chemistry (8th Edition), Chapter 11, Problem 11.21UKC

Figure 1

From the above figure,

We know that, yellow spheres are representing 1228Mg and blue spheres are 1328Al

The total number of yellow spheres present in first box is 16

The number of yellow spheres present in second box after beta decay is 4

16100%β1half-life850%β2 half-life425%

So, the number of half-lives needed is 2

Conclusion

The number of half-lives when Mg-28 decays by β-emission to give Al-28 was calculated as two half-lives.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
A 10.00 mg sample of technetium-93 (92.91024898 u) is used to heat 125.4 g of water from 23.4 degree C to 87.4 degree C. How many minutes will be required to heat the water if all of the energy generated from the decay is used to heat the water?
Compound A has molecular formula C7H7X. Its 1H-NMR spectrum shows a singlet at 2.25 ppm and two doublets, one at 7.28 ppm and one at 7.39 ppm. The singlet has an integral of three and the doublets each have an integral of two. The mass spectrum of A shows a peak at m/z = 126 and another peak at m/z = 128; the relative height of the two peaks is 3:1 respectively. Identify what atom X is, explaining your reasoning and identify Compound A, explaining your reasoning.
Write the nuclear equation for the beta decay of Bi-214.

Chapter 11 Solutions

Fundamentals of General, Organic, and Biological Chemistry (8th Edition)

Ch. 11.5 - Prob. 11.9PCh. 11.5 - Prob. 11.10PCh. 11.5 - Prob. 11.11KCPCh. 11.6 - A -emitting radiation source gives 250 units of...Ch. 11.7 - What is the purpose of food irradiation, and how...Ch. 11.7 - What kind of radiation is used to treat food?Ch. 11.7 - A typical food irradiation application for the...Ch. 11.7 - A solution of selenium-75, a radioisotope used in...Ch. 11.7 - A typical chest X ray exposes a patient to an...Ch. 11.8 - Prob. 11.6CIAPCh. 11.8 - What advantages does MRI have over CT and PET...Ch. 11.8 - Prob. 11.8CIAPCh. 11.8 - Prob. 11.15PCh. 11.8 - The element berkelium, first prepared at the...Ch. 11.8 - Write a balanced nuclear equation for the reaction...Ch. 11.9 - What other isotope besides tellurium-137 is...Ch. 11.9 - Prob. 11.19PCh. 11.9 - One of the possible reactions for nuclear fusion...Ch. 11 - Magnesium-28 decays by emission to give...Ch. 11 - Prob. 11.22UKCCh. 11 - Prob. 11.23UKCCh. 11 - Prob. 11.24UKCCh. 11 - Prob. 11.25UKCCh. 11 - Prob. 11.26UKCCh. 11 - Prob. 11.27UKCCh. 11 - Prob. 11.28UKCCh. 11 - Prob. 11.29UKCCh. 11 - Prob. 11.30APCh. 11 - Describe how radiation, radiation, radiation,...Ch. 11 - Prob. 11.32APCh. 11 - Prob. 11.33APCh. 11 - Prob. 11.34APCh. 11 - Prob. 11.35APCh. 11 - Prob. 11.36APCh. 11 - Prob. 11.37APCh. 11 - Prob. 11.38APCh. 11 - Prob. 11.39APCh. 11 - Prob. 11.40APCh. 11 - Prob. 11.41APCh. 11 - Prob. 11.42APCh. 11 - What characteristic of uranium-235 fission causes...Ch. 11 - What products result from radioactive decay of the...Ch. 11 - Prob. 11.45APCh. 11 - Prob. 11.46APCh. 11 - Prob. 11.47APCh. 11 - Balance the following equations for the nuclear...Ch. 11 - Complete the following nuclear equations and...Ch. 11 - Prob. 11.50APCh. 11 - Cobalt-60 (half-life = 5.3 years) is used to...Ch. 11 - Prob. 11.52APCh. 11 - Prob. 11.53APCh. 11 - Prob. 11.54APCh. 11 - Prob. 11.55APCh. 11 - Selenium-75, a emitter with a half-life of 120...Ch. 11 - Prob. 11.57APCh. 11 - The half-life of mercury-197 is 64.1 hours. If a...Ch. 11 - Gold-198, a emitter used to treat leukemia, has a...Ch. 11 - Describe how a Geiger counter works.Ch. 11 - Prob. 11.61APCh. 11 - Prob. 11.62APCh. 11 - Prob. 11.63APCh. 11 - Prob. 11.64APCh. 11 - Match each unit in the left column with the...Ch. 11 - Prob. 11.66APCh. 11 - Sodium-24 is used to study the circulatory system...Ch. 11 - Prob. 11.68APCh. 11 - Prob. 11.69APCh. 11 - Prob. 11.70CPCh. 11 - Prob. 11.71CPCh. 11 - Prob. 11.72CPCh. 11 - Prob. 11.73CPCh. 11 - Prob. 11.74CPCh. 11 - Prob. 11.75CPCh. 11 - Prob. 11.76CPCh. 11 - Prob. 11.77CPCh. 11 - Prob. 11.78CPCh. 11 - Prob. 11.79CPCh. 11 - Prob. 11.80CPCh. 11 - Prob. 11.81CPCh. 11 - Prob. 11.82CPCh. 11 - Although turning lead into gold in a nuclear...Ch. 11 - Prob. 11.84CPCh. 11 - Prob. 11.85CPCh. 11 - Prob. 11.86CPCh. 11 - Prob. 11.87CPCh. 11 - Prob. 11.88CPCh. 11 - One way to demonstrate the dose factor of ionizing...Ch. 11 - One approach for treating cancerous tumors is...Ch. 11 - Prob. 11.91GP
Knowledge Booster
Background pattern image
Biochemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biochemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Principles Of Radiographic Imaging: An Art And A ...
Health & Nutrition
ISBN:9781337711067
Author:Richard R. Carlton, Arlene M. Adler, Vesna Balac
Publisher:Cengage Learning
GCSE Chemistry - Acids and Bases #34; Author: Cognito;https://www.youtube.com/watch?v=vt8fB3MFzLk;License: Standard youtube license