Zinc oxide adopts a face-centered cubic arrangement. Both Zinc ions and oxide ions adopt the face-centered cubic arrangement; with the unit cell defined by the cations overlapping the unit cell defined by the anions. What is the mass of one unit cell of zinc oxide? 6.76 x 10 23 g 4.71 x 10 23 g 9.36 x 10 21 g 5.40 x 10 22 g 7.43x 10 -22 g 1.08 x 10 22 g 2.59 x 10 23 g 6.08 x 10 22 g Next O O

Zinc oxide adopts a face-centered cubic arrangement. Both Zinc ions and oxide ions adopt the face-centered cubic arrangement; with the unit cell defined by the cations overlapping the unit cell defined by the anions. What is the mass of one unit cell of zinc oxide? 6.76 x 10 23 g 4.71 x 10 23 g 9.36 x 10 21 g 5.40 x 10 22 g 7.43x 10 -22 g 1.08 x 10 22 g 2.59 x 10 23 g 6.08 x 10 22 g Next O O

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter21: Structure And Bonding In Solids

Section: Chapter Questions

Problem 23P

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Similar questions

A portion of the crystalline lattice for potassium is illustrated below. (a) In what type of unit cell are the K atoms arranged? A portion of the solid-state structure of potassium. (b) If one edge of the potassium unit cell is 533 pm, what is the density of potassium?
What is a lattice? What is a unit cell? Describe a simple cubic unit cell. How many net atoms are contained in a simple cubic unit cell? How is the radius of the atom related to the cube edge length for a simple cubic unit cell? Answer the same questions for the body-centered cubic unit cell and for the face-centered unit cell.
MnO has either the NaCI type structure or the CsCI type structure (see Exercise 69). The edge length of the MnO unit cell is 4.47 10-8 cm and the density of MnO is 5.28 g/cm3. a. Does MnO crystallize in the NaCl or the CsCl type structure? b. Assuming that the ionic radius of oxygen is 140. pm, estimate the ionic radius of manganese.
Calculate the percent of volume that is actually occupied by spheres in a body-centered cubic lattice of identical spheres You can do this by first relating the radius of a sphere, r, to the length of an edge of a unit cell, l. (Note that the spheres do not touch along an edge but do touch along a diagonal passing through the body-centered sphere.) Then calculate the volume of a unit cell in terms of r. The volume occupied by spheres equals the number of spheres per unit cell times the volume of a sphere (4r3/3).
(a) Determining an Atom Radius from Lattice Dimensions: Gold has a face-centered unit cell, and its density is 19.32 g/cm3. Calculate the radius of a gold atom. (b) The Structure of Solid Iron: Iron has a density of 7.8740 g/cm3, and the radius of an iron atom is 126 pm. Verify that solid iron has a body-centered cubic unit cell. (Be sure to note that the atoms in a body-centered cubic unit cell touch along the diagonal across the cell. They do not touch along the edges of the cell.) (Hint: The diagonal distance across the unit cell = edge 3.)