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You are again creating PET (repeat unit molecular weight = 192 g/mol) through reaction of a diacid and a diol. What will be the maximum number-average molecular weight attainable if you start with 2.85 moles of the diacid and 2.9 moles of the diol, assuming 99.9% conversion? *To avoid confusion caused by significant figures, carry values to three decimal places throughout your calculations r= ΝΑ = NB Xn (1+r) (1+r) - 2rp

You are again creating PET (repeat unit molecular weight = 192 g/mol) through reaction of a diacid and a diol. What will be the maximum number-average molecular weight attainable if you start with 2.85 moles of the diacid and 2.9 moles of the diol, assuming 99.9% conversion? *To avoid confusion caused by significant figures, carry values to three decimal places throughout your calculations r= ΝΑ = NB Xn (1+r) (1+r) - 2rp

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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You are again creating PET (repeat unit molecular weight = 192 g/mol) through reaction of a diacid and a diol. What will be the maximum number-average molecular weight attainable if you start with 2.85 moles of the diacid and 2.9 moles of the diol, assuming 99.9% conversion? *To avoid confusion caused by significant figures, carry values to three decimal places throughout your calculations r ΝΑ NB O 20000 g/mol O 32000 g/mol O 12000 g/mol 28000 g/mol Xn = (1 + r) (1 + r)- 2rp
Transcribed Image Text:You are again creating PET (repeat unit molecular weight = 192 g/mol) through reaction of a diacid and a diol. What will be the maximum number-average molecular weight attainable if you start with 2.85 moles of the diacid and 2.9 moles of the diol, assuming 99.9% conversion? *To avoid confusion caused by significant figures, carry values to three decimal places throughout your calculations r ΝΑ NB O 20000 g/mol O 32000 g/mol O 12000 g/mol 28000 g/mol Xn = (1 + r) (1 + r)- 2rp
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