y y 60 kN 60 kN D D 40 kN 7 m 7 m C Ax tA 3 m Cy Ay Cy Ax AtA, - 4 m - - 4 m- Elevation - 4 m- 40 kN D 3 m A Ax Az Z. Plan

Q: 8a kN a kN/m A -4.00- -6.00–

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Q: 1. Determine las coordenadas del centroide de la siguiente figura. 4a 3a

A: solved

Q: urlin spacing 1.5m lope 15 degrees read Load- 2.5kPa ve Load- 2.5kPa Wind Load 1.0Pa Vindward…

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Q: bo kn 1.5m

A: The given beam is analyzed using the equation of equilibrium forces. The algebraic sum of vertical…

Q: R= 10.2 m 95 8 m 40 HE TI tW = 1050 KN 4 m Fig.4

A: The answer is found to be, Factor of safety of the given slope FOS=2.38 For explanation please see…

Q: Question: Given The Following Differential Level Notes: STA BS HI FS ELEVATION BM-A 1.73 346.50 ...…

A: given - differential level notes. to find - point of highest elevation

Q: 0.75 m 20 KN Cl 1.2 m 20 KN 1m D DE

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Q: y at a distance 3m From 20 KN lom' OF R.1 21 R2

A: To find deflection at 3m from R1

Q: Q.I A line of level is run from B.M.1 (elevation=102.00m) to B.M. 2(elevation=106.00m). The field…

A: Given Elevation of BM1 = 102 Elevation of BM2 = 106 Reading of BS, IS and FS To Determine Computed…

Q: w (kN/m) A 1.5EI D El TTTT.

A: Can you please provide the figure correctly

Q: Assume Cd = 0.60 * 1 ft 60° 0.5 ft weir plate

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Q: At A , PA = Ka 9 : 0:219 x40 %3D 8.76 KN/m At B, Ka 9 + Ka Y Z 8.76+ 0.219 x 19 x 20 %3D 91.98 KN/m…

A: this is the active case in cohesion soilfirst of all you have to determine,active earth pressure at…

Q: surfaces of CO 100 KN P F 30°. 30° 15 R

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Q: system primar e followings 50 kN/m? а) о — 150 kРа Sand Yt = 18.7 kN/m3 5 m b) o = 175 kPa c) o =…

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Q: A square foundation is shown in Figure P4.12. Use FS = 6, and determine the size of the foundation.…

A: Given:- A square foundation is shown  The magnitude of the load acting on the foundation (P) = 450…

Q: 160.00 kN 2 m 10.00 kN 10 -2.67 m @ 3

A: Find the internal member force of member 6,7 and 9 using appropriate method

Q: 2 kN/m C 1.5 kN 5 kN/m 6 m 1m TEE 4 m 0.8 m

A: (a) ∑Fy=0; VA=0∑Fx=0; HA=2×4=8 KN∑MA=0; MA=2×4×2=16 KN-m Member Axial force diagram Shear force…

Q: 10. Complete the following table using the knowledge obtained in class about differential leveling…

A: Complete the following table using the knowledge obtained in class about differential leveling

Q: ground surface Y-15.6 kNm3 Ysar-16.6 kN/m³ 4 m water table Clay 5 m Ysar=17.8 kN/m

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Q: B) RA =, KN, R = KN/m 60 KN/m 55KN 175 KN A 6.00 m R 1.50 m 4.00 m

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Q: Ra and Rb 10ok 200 kN 500KN.m 200 KN.M Ra Ro

A: as per our policy we should answer only one question at a time. so, i am answering only first…

Q: Determine the T3, If y=18m. * 10 m 60 KN 40 KN 80 KN 50m 30 m 50m -30m O 158.678 KN O 179.013 KN O…

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Q: 20. A trapezoidal canal, 6m at the bottom and having side slopes 2:1 carries water to a depth of…

A: Given data B = 6 m  y = 40cm = 0.4 m  Side slope n:1 = 2:1 -----> n = 2  Velocity (v) = 0.6 m/s

Q: 150 kN 24 kN/m A |D BO00 C 000 2 m 1 m 0.5 m0.5 m

A: The degree of static indeterminacy = 4-3 =1. The moment at B is taken as redundant R and the basic…

Q: B) RA =, KN, Rg = KN/m %3D 45 KN/m 250 KN A 6.00 m Rg 1.50 m 4.00 m

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Q: 2.8 m. 43¹ 5.6 KN 3.2 m 6.0 KN R BC.CO 3.2 m

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Q: w = 14 kN/m, ME 3 kNm, and RA = 7.92 kN w kN/m MẸ kNm в A B C D E 0.8m 1.0m 0.7m 2.0m RA M(x) cut

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Q: *I WATER IC FLW me IN A tRAFE Z0IDAL CHANNEL WITH A SIDE SLOPES EQUAL to 2H V AND *15 t BTm wrot AT…

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Q: Determine bar force member EF

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Q: 21(KN) 14 7(KN/m) 35ckN.m) 2, 4 2

A: Consider free body diagram of the beam shown below.

Q: 13.35 kN 40° 1.22 m 1.83 m A \D 2,44 m Figure P4.137

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Q: 2 40° F = 5 kN 30° A PROBLEM 2/91 --y

A: Express F as a vector in terms of the unit vectors i, j, and k. Determine the projection, both as a…

Q: 6 KNIM 45 KN/m コ行个1个才 3m 3.6m

A:

Q: BC and BD.( 100 KN 150 KN 4.00 meters 5.00 m 4.00 meters 2.00 meters 2.00 meters

A: To find support reaction and force in member BC,BD

Q: Figure 03 "W, KN/m" 4.25m 5.15m b2= 0.55m b3= 0.75m "Wx1/2m, KN" h2= 0.75m h3= 0.75m 9.95m L4, m b1=…

A:

Q: A 1.75 m Area = 800 mm² B 1.25 m C Area = 500 mm² 75 kN 1.5 m D 50 kN P.

A: Determine the deformation of point b in mm

Q: C.L Elev.=??m 17 m 1 5 m 3 m 7 m Elev.=15m 1 4 ?? m Elev.=13m Elev.F12m 3.

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Q: -kN, b- 39.2 kN, c = 2.7 m a" kN D H "c" m b" kN C K "c" m b" kN B J "c" m 4 m 5 m A = 40 x 10º mm?…

A:

Q: A) RA = KN, R = KN 1 50 KN 40 KN/m 275 KN 1m 1.5m 1m 1.5 m A 3.00 m

A: Given simply supported beam with loading conditions. It is asked to find support reactions at A…

Q: Q1 B) Find Q in 1/s and -V½= 2.5 m/s -D;= 300 mm find V3 in ft/min Q=? V, = 3 m/s D1 = 500 mm Vz = ?…

A: Discharge is the main quantity in any field used to transfer fluids from one place to another. It…

Q: 3130 KN 220 KN 20 20° 2.0 m E Av = 2.0 m Ah = Rp = D 3.5 m 3.5 m AB = DE = EC= BC = BE= CD= AE =

A: Using equilibrium equation

Q: Homework: Draw S.F.Ds and B.M.D 12 kN/m 40 kN В 2 m 1 m

A: As per guidelines we can solve one question at time, please upload separately,Thanks Solution to…

Q: Q.I A line of level is run from B.M.I (elevation=106.40m) to B.M. 2(elevation=110.50m). The field…

A: To find reduce levels and adjusted levelsof points 2,3,4 and 5

Q: A 3 20 KN B D 3 12 kN C

A:

Q: 20. A trapezoidal canal, 6m at the bottom and having side slopes 2:1 carries water to a depth of…

A: B = 6m  Side slope 2:1 = n:1 ---> n = 2  V = 0.6 m/s

Q: 45D |1m im H F E 7.5 kN V 5 kN 0.5 m 1m 1m 1m

A:

Q: Given the Levelling Notes: Sta. B.S. H.I. F.S. Elev. BM 1 1.21 50.00 ТР 1 6.20 4.65 TP 2 4.82 3.11…

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Q: 2- Using Meyerhof Eq 12.18 for Qp and Eq 12.42 & 12.43 Q, find Qult 0.5mø CONCRETE 4,=320 Y = 18.5…

A: Meyerhof method gives the resultant load at the bearing level is vertical and  the horizontal…

Q: P? Using appreximate hetked of analysis, find the internal forees at sec. a-a and sec.b-b and Sec.…

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Q: Station 2 + 020 a o b +3.15 2.65 2.5 Station 2+ 080 Co d -2.5 -3.65 2.5 Base for cut = 12 m,…

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Plane and Space Trusses

In civil engineering, a truss is the most important structure that forms the most fundamental member of any building structure and commercial complexes. Trusses are composed of individual members or links that are interconnected by suitable joints, such as rivets, welds, or bolts, and nuts. In trusses, the interconnection leads to the formation of a series of triangles joined together such that all the triangular members behave as a single rigid body. In a simple truss, three members are connected to form a truss member. In trusses, the force always acts at the joints or the interconnection between the individual members.