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- Q3a) Determine the reaction moments at the supports by using Moment-Distribution Method. Assume A and C are fixed, and B is a pin joint. E-200 GPa and 1-50x10" mm. 1000 N/m 4EI EI A B C 1 m 1 m 1 m 1 m PLEASE SEE TABLE Q3a NEXT PAGE FOR THIS PROBLEM!Situation 7 - Refer Figure shown. 18. Calculate the reaction at D, in kN. Answer: 52.5 kN 19. Determine the total reaction at B. 4 m C, in kN. Answer: 60.47 kN 2 m 6 m 3m 20 kN 10 kN1) Assume q, = 2kN/m and g. = 4 kN/m and a = 2 m and b= 3 m. Find the support reactions. 90 A A, =. units_ A =. B, = =
- Q.3] Find the reactions at A and B for the structure shown in the figure. 2 kN/m 20KN 2m | lem 2m bm AKN/M1) Find the support reactions at static equilibrium for the loaded beam shown below in Fig4.1 6' 1000lb 400lb 600lb/ft 5' A AB -400lb 12.5 15 Fig4.11.2 p kN q kN/ m L = 14 m d = 4 m q = 100 kN/m p = 50 kN A В A Simply supported beam is Lm long and is subjected to a uniformly distributed load of q ķN/m applied for the full length of the beam and a concentrated load of p kN of the beam as shown. Draw the free body diagram of the given beam and find the support reactions.
- 6000 ft-lb |--3 A -3 ft- y A) Draw a free body diagram of the bar AB. B) Compute the reactions at A and B. X 400 lb/ft -10 ft- B 1000 lb -2 ft→Problem 3: A bent beam ABCD is held in equilibrium by a roller at A and by a pinned connection at D. The beam supports a uniform distributed load (80 lb/ft) over section AB and a concentrated force (390 lb) at point C. The roller at A rests against an inclined surface that is oriented 30° from the horizontal direction. Neglect the weight and depth of the beam and the size of the roller in this analysis. (a) Draw a complete FBD of beam ABCD. Clearly label all loads, reactions, and distances. (b) Determine all reactions at A and D. 80 lb/ft 30°/ 8 ft B 4 ft D 390 lb 12/12 3 ftAs shown in figure, the intensity of loading on a simply supported beam 10 ft long is given by y = 10x3 where y is in lb/ft and x is in ft measured from A. Find the reactions at A and B.
- 13)The Beam in figure below is weightless. A moveable weight(mass)W of 300 lbm is to be attached as shown. 420 Ibf 640 bf 3.0 ft 6.0 ft 6.0ft rove A d) Determine summation of moments respect to point A and set =0 (EMA=0) e) from above equations, determine the location x of the weight so that the vertical reactions at A and B are equal.(1) IN Z 60 in B cord ले Q=ib 70 in 10 insi C In cord 42 (W = TBD A 1 16 45 in P = 42 16 Q = 54 16 x A block of weight W is suspended by two cords, AC and BC, shown, and forces P (in the x direc) and Q (in the z direc) are exerted at C. Find the weight W of the block, and the fensions TAC and Ter in the two cords. Ас BCModulus E of elasticity, for the ACB beam with inertia I; a- Find the elastic curve equation with the singularity equation. b- Find the reaction forces at Point A. c- Find the reaction force at Point B. (2/3) W 2W A W -L/2 L