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A: Formula of lead nitrate = Pb(NO3)2 Formula of sodium chloride = NaCl Pb(NO3)2 reacts with NaCl.
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A: Writing the balanced chemical equation meuld be:2(NH4)3 Po4 + 3 Na2 So4 ⇌3(NH4) so4 + 2 Na3PO4
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- The Handbook of Chemistry and Physics (http://openstaxcollege.org/l/16Handbook) gives solubilities of the following compounds in grams per 100 mL of water. Because these compounds are only slightly soluble, assume that the volume does not change on dissolution and calculate the solubility product for each. (a) BaSiF6, 0.026 g/100 mL (contains SiF62- ions) (b) Ce(IO3)4, 1.5102 g/100 mL (c) Gd2(SO4)3, 3.98 g/100 mL (d) (NH4)2PtBr6, 0.59 g/100 mL (contains PtBr62- ions)12.17 Which of the following is more likely to precipitate sulfate ions? PbSO4(s) Pb*+(aq) + SO42’(aq) K = 1.8 X IO"8 CaSO4(s) i=i Ca2+(aq) + SO42'(aq) K = 9.1 X 10-6A mountain lake that is 4.0 km × 6.0 km with an average depth of 75 m has an H+(aq) concentration of 1.3 × 10−6 M. Calculate the mass of calcium carbonate that would have to be added to the lake to change the H+(aq) concentration to 6.3 × 10−8 M. Assume that all the carbonate is converted to carbon dioxide, which bubbles out of the solution.
- According to the Resource Conservation and Recovery Act (RCRA), waste material is classified as toxic and must be handled as hazardous if the lead concentration exceeds 5 mg/L. By adding chloride ion, the lead ion will precipitate as PbCl2, which can be separated from the liquid portion. Once the lead has been removed, the rest of the waste can be sent to a conventional waste treatment facility. How many grams of sodium chloride must be added to 500 L of a waste solution to reduce the concentration of the Pb2+ ion from 10 to 5 mg/L?Complete the balanced neutralization equation for the reaction below: NH,OH(aq) + H,PO,(aq) – O4- 3- | 2+ 3+ O 4+ 1 4 6. 7 8 9. O4 O7 (s) (1) (g) | (aq) + P + Reset • x H,O Delete LO 2. 3.Module 8: H X 7087483#/7087483/16/2 % General Chemistry 4th Edition McQuarrie Rock Gallogly Question 25 of 35 - Module 7 Ho X [13] = x10 TOOLS Topic: Week 4 Discussion Resources C Give Up? The amount of I5 (aq) in a solution can be determined by titration with a solution containing a known concentration of S₂O3(aq) (thiosulfate ion). The determination is based on the net ionic equation 2S₂O3(aq) + 13(aq) →SO (aq) +31-(aq) Given that it requires 41.0 mL of 0.450 M Na₂S₂O3(aq) to titrate a 20.0 mL sample of I3 (aq), calculate the molarity of 15 (aq) in the solution. Hint University Science Books presented by Macmillan Learning M Question Source: McQuarrie, Rock, And Gallogly 4e-General Chemistry C C
- Consider the following equilibrium: Cu²+ (aq) + 4NH3(aq) Cu(NH3)4²+ (aq) (Kf = 4.8e+12) A solution is made by mixing 15.0 mL of 0.90 M CuSO4 and 1.00 L of 0.530 M NH3. Assume additive volumes to answer the following questions. Give all answers to three sig figs. a) What is the concentration of NH3 in the resulting solution? [NH3] = M b) What is the concentration of Cu(NH3)42+ in the resulting solution? [Cu(NH3)4²+] = M c) What is the concentration of Cu²+ in the resulting solution? [Cu²+] = MThe scientist starts with four solutions made of water-soluble salts. Solution A contains sodium arsenate. Solution B contains ammonium oxalate. Soution C contains silver chlorate. Solution D contains aluminum bromide. Solution Solute Color of Solution A Na3AsO4Na3AsO4 colorless B (NH4)2C2O4(NH4)2C2O4 colorless C AgClO3AgClO3 colorless D AlBr3AlBr3 yellow The results of mixing each solution in pairs are shown in the table. Experiment Solutions Mixed Result 1 A + B no precipitate, colorless solution 2 A + C brown precipitate 3 A + D white precipitate 4 B + C white precipitate 5 B + D white precipitate 6 C + D yellow precipitate Identify the formula for each precipitate that forms. precipitate from A+C: precipitate from A+D: precipitate from B+C: precipitate from B+D: precipitate from C+D:Consider the following equilibrium: Cu²+ (aq) + 4NH3(aq) Cu(NH3)4²+₁ (aq) (Kf = 4.8e+12) A solution is made by mixing 15.0 mL of 0.90 M CuSO4 and 1.00 L of 0.530 M NH3. Assume additive volumes to answer the following questions. Give all answers to three sig figs. a) What is the concentration of NH3 in the resulting solution? [NH3] = .47 M b) What is the concentration of Cu(NH3)42+ in the resulting solution? [Cu(NH3)4²+] = 5.3e-2 X M c) What is the concentration of Cu²+ in the resulting solution? [Cu²+] = 5.3e-2 X M
- Which of the following would, if mixed with aqueous K2SO4, yield a solid, insoluble precipitate? Group of answer choices Ba(NO3)2 (aq) NaI (aq) LiOH (aq) NH4C2H3O2 (aq) NaNO3 (aq)35 of 44 > A monoprotic weak acid, HA, dissociates in water according to the reaction HA(aq) + H,O(1) = H,O*(aq) + A (aq) The equilibrium concentrations of the reactants and products are (HAJ = 0.270 M. [H,O*] = 3.00 x 10 M, and |A] = 3.00 x 10 M. Calculate the K, value for the acid HA. K, =Al203 (s) = 2AI3+ (aq) + 302- (ag) If, at equilibrium, a beaker contains 1.00 L of solution with 19.2 grams of Al203, 0.338 M AI3+ and 0.0593 M O2-, what is the Ke value for the reaction above? (the answer should be entered with 3 significant figures; do not enter units; give answer in scientific notation--valid notation examples include 1.23e-8 and 1.23e8 and -1.23e-4 and 1.23e0)