Write an assembly language program to calculate the sum of series of the even numbers.Input: 2200H = 04H 2201H = 10H 2202H = 09H 2203H = 13H 2204H = 18HStore the result in the memory location 2210H.Program: #ORG 2000HLDA 2200 // Load the Accumulator content from the memory 2200 MOV C,A // Move the content of Accumulator to Register C MVI B,00 // Reset the content of Register B with 00LXI H,2201 // Load the HL pair with the address 2201 BACK: MOV A,M // Move the content of the Memory to AccumulatorANI 01 // Add Immediate Data 01 with the content of Accumulator JNZ SKIP // Jump No Zero, Go to SkipMOV A,B // Move the content of Register B to AccumulatorADD M // Add the Accumulator content with the Memory SKIP:MOV B,A // Move the Content of Accumulator with Register B INX H // Increment HL PairDCR C // Decrement the content of Register CJNZ BACK // Jump No Zero, Go to BACKSTA 2210 // Store the Accumulator Content to the memory location 2210 HLT // Halt the Program # ORG 2200H# DB 04H, 10H, 09H, 13H, 18H Question:Write an assembly language program to calculate the sum of series of the evennumbers.Input: 2200H = 04H2201H = 10H2202H = 09H2203H = 13H2204H = 18HStore the result in the memory location 2210H.Program:#ORG 2000HLDA 2200 // Load the Accumulator content from the memory 2200MOV C,A // Move the content of Accumulator to Register CMVI B,00 // Reset the content of Register B with 00LXI H,2201 // Load the HL pair with the address 2201BACK: MOV A,M // Move the content of the Memory to AccumulatorANI 01 // Add Immediate Data 01 with the content of AccumulatorJNZ SKIP // Jump No Zero, Go to SkipMOV A,B // Move the content of Register B to AccumulatorADD M // Add the Accumulator content with the MemoryMOV B,A // Move the Content of Accumulator with Register BSKIP: INX H // Increment HL PairDCR C // Decrement the content of Register CJNZ BACK // Jump No Zero, Go to BACKSTA 2210 // Store the Accumulator Content to the memory location 2210HLT // Halt the Program# ORG 2200H# DB 04H, 10H, 09H, 13Н, 18H After the execution of the code:Content of Memory location → 2200:Content of Memory location 2201:Content of Memory location → 2202:Content of Memory location → 2203:Content of Memory location → 2204:Content of Memory location → 2210:Hexcode of the program:AddressLabelMnemonic Hex code2000200120022003200420052006200720082009200A200B200C200D200E200F2010201120122013201420152016201720182019201AStatus of Memory:Hex Code ValueMemoryAccumulatorRegister BRegister CRegister DRegister ERegister HRegister LMemory(M)220022012202220322042210

Question

Write an assembly language program to calculate the sum of series of the even numbers.Input: 2200H = 04H 2201H = 10H 2202H = 09H 2203H = 13H 2204H = 18HStore the result in the memory location 2210H.Program: #ORG 2000HLDA 2200 // Load the Accumulator content from the memory 2200 MOV C,A // Move the content of Accumulator to Register C MVI B,00 // Reset the content of Register B with 00LXI H,2201 // Load the HL pair with the address 2201 BACK: MOV A,M // Move the content of the Memory to AccumulatorANI 01 // Add Immediate Data 01 with the content of Accumulator JNZ SKIP // Jump No Zero, Go to SkipMOV A,B // Move the content of Register B to AccumulatorADD M // Add the Accumulator content with the Memory  SKIP:MOV B,A // Move the Content of Accumulator with Register B INX H // Increment HL PairDCR C // Decrement the content of Register CJNZ BACK // Jump No Zero, Go to BACKSTA 2210 // Store the Accumulator Content to the memory location 2210 HLT // Halt the Program # ORG 2200H# DB 04H, 10H, 09H, 13H, 18H Question:Write an assembly language program to calculate the sum of series of the evennumbers.Input: 2200H = 04H2201H = 10H2202H = 09H2203H = 13H2204H = 18HStore the result in the memory location 2210H.Program:#ORG 2000HLDA 2200 // Load the Accumulator content from the memory 2200MOV C,A // Move the content of Accumulator to Register CMVI B,00 // Reset the content of Register B with 00LXI H,2201 // Load the HL pair with the address 2201BACK: MOV A,M // Move the content of the Memory to AccumulatorANI 01 // Add Immediate Data 01 with the content of AccumulatorJNZ SKIP // Jump No Zero, Go to SkipMOV A,B // Move the content of Register B to AccumulatorADD M // Add the Accumulator content with the MemoryMOV B,A // Move the Content of Accumulator with Register BSKIP: INX H // Increment HL PairDCR C // Decrement the content of Register CJNZ BACK // Jump No Zero, Go to BACKSTA 2210 // Store the Accumulator Content to the memory location 2210HLT // Halt the Program# ORG 2200H# DB 04H, 10H, 09H, 13Н, 18H After the execution of the code:Content of Memory location → 2200:Content of Memory location > 2201:Content of Memory location → 2202:Content of Memory location → 2203:Content of Memory location → 2204:Content of Memory location → 2210:Hexcode of the program:AddressLabelMnemonic Hex code2000200120022003200420052006200720082009200A200B200C200D200E200F2010201120122013201420152016201720182019201AStatus of Memory:Hex Code ValueMemoryAccumulatorRegister BRegister CRegister DRegister ERegister HRegister LMemory(M)220022012202220322042210

Accepted Answer

Output Result 2210H= 10H +18H= 28H
CODE:
LDA 2200H
;"counter initialization"
MOV C, A
;"assign 0 in…

Write an assembly language program to calculate the sum of series of the even numbers. Input: 2200H = 04H 2201H = 10H 2202H = 09H 2203H = 13H 2204H = 18H