Which XXX would replace the missing statement in the following algorithm? ListInsertAfter(students, curNode, newNode) { if (students-head -- null) { studentshead - newNode studentstail - newNode XXX { students-tail-next - newNode newNodeprev - studentstail students-tail - newNode else { sucNode - curNodenext newNode-next = sucNode newNodeprev - curNode curNode-next - newNode sucNodeprev - newNode

Which XXX would replace the missing statement in the following algorithm? ListInsertAfter(students, curNode, newNode) { if (students-head -- null) { studentshead - newNode studentstail - newNode XXX { students-tail-next - newNode newNodeprev - studentstail students-tail - newNode else { sucNode - curNodenext newNode-next = sucNode newNodeprev - curNode curNode-next - newNode sucNodeprev - newNode

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Identify the correct algorithm for reverse traversal in the doubly-linked list studentList. Group of answer choices ListTraverseReverse(students) {curNode = students⇢headwhile (curNode is not null) {Print curNode's datacurNode = curNode⇢next}} ListTraverseReverse(students) {curNode = students⇢headwhile (curNode is null) {Print curNode's datacurNode = curNode⇢prev}} ListTraverseReverse(students) {curNode = students⇢tailwhile (curNode is not null) {Print curNode's datacurNode = curNode⇢next}} ListTraverseReverse(students) {curNode = students⇢tailwhile (curNode is not null) {Print curNode's datacurNode = curNode⇢prev}}
Hypertune these parameters by using grid search: stack_rgs = StackingRegressor(estimators = [ ('ridge_regression', Ridge(random_state=42)), ('sgdregressor', SGDRegressor(random_state=42)), ('svr', SVR(kernel='rbf'))
The add operation is the only way an element can be added to an ordered list. Nolocation is specified in the call because the elements themselves determine their order.Very much like the remove operation, the add operation requires a combination ofcomparisons and shifts: comparisons to find the correct location in the list and thenshifts to open a position for the new element. Looking at the two extremes, if theelement to be added to the list belongs at the front of the list, that will require onecomparison and then the other n – 1 elements in the list will need to be shifted. If theelement to be added belongs at the rear of the list, this will require n comparisons, andnone of the other elements in the list will need to be shifted. Like the remove operation, the add operation requires n comparisons and shifts each time it is executed, andthus the operation is O(n). implemente The add operationd?
How many nodes will be visited during a search for a node that is in a linked list with N nodes? Describe the best- and worst-case scenarios for a search. Explain why a singly-linked list has the RemoveAfter() function while a doubly-linked list has the Remove() function. Is it possible to create a RemoveAfter() method for a doubly-linked list as well? Explain why you think that is or why you don't think that is. Is it possible to create a Remove() method for a singly-linked list as well? Explain why you think that is or why you don't think that is.
How many nodes will be traveled to find a node in a linked list with N nodes? Describing the best and worst case searchesWhat is the difference between a single-linked list and a double-linked list?Could a doubly-linked list have a RemoveAfter() function? Why or why not?Could a single-linked list have a Remove() function? Why or why not?
Add to LinearProbingHashST a delete()method that deletes a key-value pair by setting the value to null (but not removingthe key) and later removing the pair from the table in resize(). Your primary challenge is to decide when to call resize(). Note : You should overwrite the null value ifa subsequent put() operation associates a new value with the key. Make sure that yourprogram takes into account the number of such tombstone items, as well as the numberof empty positions, in making the decision whether to expand or contract the table
Implement solution for remove(int id) removes the Student associated with this id; if the id is not found in the table or on the waitlist, then it should return null; otherwise, it should return the Student associated with the id. If the student that is removed was registered, then this student should be replaced by the student who is first in the waitlist queue. If the student who is removed was on the waitlist, then they should just be removed from the waitlist. You should go directly to slot id % m rather than iterating through all the slots. public class Course { public String code; public int capacity; public SLinkedList<Student>[] studentTable; public int size; public SLinkedList<Student> waitlist; public Course(String code) { this.code = code; this.studentTable = new SLinkedList[10]; this.size = 0; this.waitlist = new SLinkedList<Student>(); this.capacity = 10; } public…
Note: Ungraded Question related to skiplist. Design, a version of a skiplist that implements the SSet interface, but also allows fast access to elements by rank. That is, it also supports the function get(i), which returns the element whose rank is i in O(log n) expected time. (The rank of an element x in an SSet is the number of elements in the SSetthat are less than x.)Describe how your version differs from a regular skiplist and provide pseudocode of find(x) and get(i) for this version.
For the AVLTree class, create a deletion function that makes use of delayed deletion.There are a number of methods you may employ, but one that is straightforward is to just include a Boolean variable in the Node class that indicates whether or not the node is designated for deletion. Then, all of your other techniques must take this field into consideration.
Starting with an Empty descendent-Sorted Singly-Linked List draw its status after each operation. add(20); sortedInsert(10); sortedInsert(25); deleteFromHead(); sortedInsert(15); deleteFromTail();
Implement solution for remove(int id) removes the Student (classt type) associated with this id; if the id is not found in the table or on the waitlist, then it should return null; otherwise, it should return the Student associated with the id. If the student that is removed was registered, then this student should be replaced by the student who is first in the waitlist queue. If the student who is removed was on the waitlist, then they should just be removed from the waitlist. You should go directly to slot id % m rather than iterating through all the slots. public class Course { public String code; public int capacity; public SLinkedList<Student>[] studentTable; public int size; public SLinkedList<Student> waitlist; public Course(String code) { this.code = code; this.studentTable = new SLinkedList[10]; this.size = 0; this.waitlist = new SLinkedList<Student>(); this.capacity = 10; }…
Consider the following code that uses a list of n elements (alist). What is the worst case runtime of this algorithm? def my_func(alist): for item in alist: return item >= alist[len(alist)-1] for item in alist: return item == alist[0] for item in alist: return item != alist[len(alist)//2] Question 11 options: O(n^2) O(n) O(n log n) O(log n) O(1)