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When the Hg2+ concentration is 1.50 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 1.664V. What is the Cr³+ concentration? 3Hg2+ (aq) + 2Cr(s) 3Hg(1) + 2Cr³+ (aq) Answer: M

When the Hg2+ concentration is 1.50 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 1.664V. What is the Cr³+ concentration? 3Hg2+ (aq) + 2Cr(s) 3Hg(1) + 2Cr³+ (aq) Answer: M

General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter19: Electrochemistry
Section: Chapter Questions
Problem 19.88QP: Calculate the cell potential of a cell operating with the following reaction at 25C, in which...
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When the Hg2+ concentration is 1.50 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 1.664V. What is the Cr³+ concentration? 3Hg2+ (aq) + 2Cr(s)→→→3Hg(1) + 2Cr³+ (aq) Answer: M
Transcribed Image Text:When the Hg2+ concentration is 1.50 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 1.664V. What is the Cr³+ concentration? 3Hg2+ (aq) + 2Cr(s)→→→3Hg(1) + 2Cr³+ (aq) Answer: M
When the Hg2+ concentration is 9.87×10-4 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 1.503V. What is the Cr³+ concentration? 3Hg²+ (aq) + 2Cr(s)→→3Hg(1) + 2Cr³+ (aq) Answer: M
Transcribed Image Text:When the Hg2+ concentration is 9.87×10-4 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 1.503V. What is the Cr³+ concentration? 3Hg²+ (aq) + 2Cr(s)→→3Hg(1) + 2Cr³+ (aq) Answer: M
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