What will be the value of the variable x after the execution of the program? %#3include < int main() { int x; x = 10; if (x<10) X -= 10; else if (x>10) x += 00; else if (x) x += 10; else -= 10; return 0; Answer:
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- int y=0,i; for (int i=0;i<10;++i) y+=i; 36 66 45 55What is the final value of y? int x = 4; 6; int y if (x < 10) { if (y < 5) { y = y + 1; } } else { } y = 7; } else { y = y + 10;i. Find the loop invariant for the program code below. void main() { int y = 1, x = 0; while (x < 4) { y = y * z; x = x + 1; }
- int test(int *x, int y){ x=&y; return(*x+y); } int main(void) { int x=1, y=6; test(&y, x); printf("%d %d %d", x, test (&y,x),y); return 0; } 1 2 63. int x =9 ;display the address of the variable x? Answer:2) What does this code output? int fun(int x, int y) { if (x == 0) return 1; x = x/ 2; y = y - 1; return fun(x, y) + x + y; int main() { int a = 10; %3D int b = 10; %3! int c = fun(a, b); printf("%i\n", c); %3D return 0; 11 15 23 39
- Problem Description: In the Whimsical Library, each book is enchanted with a magical code to ensure the protection of knowledge. The validation process for these magical codes involves a combination of mathematical spells. The validation process is described as follows: Take the sum of the digits at odd positions from left to right. Take the sum of the squared digits at even positions from left to right. If the absolute difference between the results from step 1 and step 2 is a prime number, the book code is considered valid; otherwise, it is invalid. Example 1: Consider the magical book code 86420137. Step 1. Take the sum of the digits at odd positions from left to right. 8+4+0+3=15 Step 2. Take the sum of the squared digits at even positions from left to right. 6^2+2^2+1^2+7^2=36+4+1+49 = 90 Step 3. If the absolute difference between the results from step 1 and step 2 is a prime number. 115-901 75 (not a prime number) Book code 86420137 is invalid. Example 2: Now, let's examine the…The value of x at the end.int x = 1;x = x + 1;x++;int m =0; while(++m < 2 ) System.out.print( m ); System.out.print( m ); a. 112233 Ob. 12 C. 123 Od. 001122
- int main() { } above? int a, b, c, d; a 4; 22; 32; 42; CDCD b с d if(b%a { } if(c%a { 0) printf("hello"); } else { } else if(d%a 2) { } printf("hi"); printf("yes"); if(d>b) { } printf("no"); What is the output of the program shown(iii) int x = 10; while (x != 16) { } LINE System.out.print (x + if (even (x)) { X = = x / 2; } else { X } X = 3 x + 1; * "); System.out.println(x); // L7 Assume the method even returns true if the argument is an even number, and false otherwise. // L1 // L2 // L3 // L4 // L5 Complete the dry run table (you may not need all rows): x != 16 ? // L6 even (x) ? Printedin this code, the integer on each line shows the line number that is not part of code: what is he local variables of sum: ____ 1 public static int sum(int x, int y){ 2 int z = x +y; 3 return z; 4 } 5 public static void main(String[] args){ 6 … 7 sum(a+2, b); 8 … 9 }