What is the value of pMg for 50.0 ml of a 0.0500 M Mg*2 solution buffered at pH 10.00 and titrated with 0.0500 m EDTA when 51.0 mL of EDTA is added (Kf = 6.2x108)(ay4. = 0.30 )? 1. O6.57 2. O2.88 3. O4.94 4. O1.39 5. 07.96
Q: If 200 ml of 0.01 M EDTA is added to 100 ml of 0.01 M Ni solution that is buffered at PH of 10.2,…
A:
Q: Consider the titration of 25.0 mL of 0.020 0 M MnSO4 with 0.010 0 M EDTA in a solution buffered to…
A:
Q: A 50.00-mL aliquot of solution containing 0.358 of MgSO4 (FM 120.37) in 0.500 L required 38.08 mL of…
A: Solution - According to the question - Given - Total Moles of Mg2+ = moles of MgSO4 = mass/molar…
Q: For the titration of 50.00 mL of 0.000226 M Ba²* with 0.100 M EDTA at pH 10.00, ay = 0.30, and Kf =…
A:
Q: A 50.00 ml aliquot solution containing 0.524 g of magnesium sulfate (FW 120.37 in 0.500 L required…
A: Given that - Volume of magnesium sulfate = 50.00 mL Mass of magnesium sulfate in 0.500 L Solution…
Q: 50.00 mL of a solution containing iron (II) and iron (III) when titrated at pH2.0, 12.50 mL 0.01200…
A: Answer is explained below. From the given plot it is clear that at ph = 2.0, only Fe3+ reacts with…
Q: A 50.00 mL sample of hard water is titrated with 0.0102 M EDTA solution (volume of blank titration=…
A: Given data,Volume of sample=50mLMolarity of EDTA=0.0102MVolume of EDTA=22.44mLVolume of EDTA for…
Q: 150.0 mL sample of 0.080 M Ca is titrated with 0.080 M EDTA at pH 9.00. The value of log K for the…
A:
Q: (a) Sketch a titration curve for a 50.0 mL of 0.01M Sr2+ solution, buffered at pH 11 when 0.0,10.0,…
A: Answer is explained below.
Q: A 60.00 mL of buffered solution (pH 10) containing Zn2* and Ni2* ions (from a chip sample) is…
A: Metal ion combine with EDTA in 1 : 1 mole ratio. So we would calculate moles of both metal ions…
Q: 25.00 mL 0.01000 M Ni2+ is titrated with 0.01000 M EDTA in a solution buffered topH 5.0. Given that…
A:
Q: What is the value of pMg for 50.0 ml of a 0.0500 M Mg solution buffered at pH 10.00 and titrated…
A:
Q: 11) What is the pM in a titration of 20.0 mL of 0.05 M Ca2 with 0.05 M EDTA if the titration is…
A:
Q: A 50.00-mL aliquot of solution containing 0.395 of MgSO4 (FM 120.37) in 0.500 L required 39.55 mL of…
A:
Q: What is the value of pMg for 50.0 ml of a 0.0500 M Mg*2 solution buffered at pH 10.00 and titrated…
A:
Q: A solution was prepared by dissolving about 30.00m g of EDTA in approximately 1 L of water and…
A: The solution is given below -
Q: 25.00 mL 0.01000 M Ni2+ is titrated with 0.01000 M EDTA in a solution buffered to pH 5.0. Given that…
A: EDTA, or ethylenediaminetetraacetic acid, is a popular chelating agent that’s used in food, as a…
Q: A 25.00 mL sample containing Fe3+ was treated with 10.00 mL of 0.03676 M EDTA to complex all the…
A: A 25.00 mL sample containing Fe3+ was treated with 10.00 mL of 0.03676 M EDTA to complex all the…
Q: In order to titrate EDTA into a water sample of unknown water hardness, the EDTA of known…
A:
Q: An EDTA solution was allowed to react with Pb²⁺ to produce 0.25 M PbY²⁻, 2.67×10⁻⁸ M Pb²⁺ and an…
A: Balanced equilibrium for the reaction of EDTA(Y4-) with Pb2+ is: Pb2+(aq) + Y4-(aq) ⇌ PbY2-(aq) ;…
Q: . The Tl in a 9.57 g sample of rodenticide was oxidized to the trivalent state and treated with an…
A: The question is based on the concept of quantitative analysis. We have to quantitatively estimate…
Q: An antacid tablet, weighing 1.25 g, was dissolved in a 1.0 L volumetric flask to allow for…
A: Given: Mass of tablet=1.25g Volume of solution=1.0L Volume of aliquot 10.0mL Molarity of…
Q: In the titration of 50.0 ml of 0.005 M Ca2+ with 0.01 M EDTA ,at pH 10 find the pCa at equivalence…
A: Given, Volume of Ca2+ = 50.0 mLMolarity of Ca2+ = 0.005 MMolarity of EDTA = 0.01 MpH = 10KCaY=…
Q: O What is the pM in a titration of 16.0 mL of 0.05 M Ca2+ with 0.05 M EDTA if the titration buffered…
A:
Q: A 50.0 mL aliquot of solution contairing 0.450 g of MgSO4 (FM 120.37) in 0.500L required 37.6 mL of…
A: EDTA titration :- It is a complexometric titrations . EDTA is short form of…
Q: C1. A carefully weighed 280mg Calcium carbonate was used in the standardization of an EDTA solution.…
A:
Q: 02) Consider the titration of 20.00mL of a Ca2+0.0250mol/L solution with 0.0500mol/L EDTA. The Ca2+…
A: 2)given, initially the volume of Ca2+ = 20.00 mL concentration of Ca2+ = 0.0250 mol/L concentration…
Q: An EDTA solution was allowed to react with Pb²⁺ to produce 0.25 M PbY²⁻, 2.67×10⁻⁸ M Pb²⁺ and an…
A: The reaction is: Pb2++EDTA⇔PbY2-
Q: Calculate a titration curve for 10.0 mL of 1.00 mM Ca?* with 1.0 mM EDTA at pH 9.0.
A: Since you have asked multiple questions, we will solve the first question for you. If you want any…
Q: 1. How much volume (mL) is needed to standardize 0.05M of EDTA using 180mg of magnesium ribbon? MW:…
A:
Q: A 0.5745 g sample of an alloy containing principally bismuth and lead is dissolved in nitric acid…
A:
Q: Q2: Consider the titration of 30.C ml of 0.015 0 M MnSO with 0.010 0 M EDTA in a salution butfered…
A: To solve the titration curve, we first need to calculate the conditional formation constant of the…
Q: 3. A solution contains 1.694 mg of CoSo. (155.0 g/mol) per milliliter. a. Calculate the volume of…
A: a) Amount of CoSO4 = 1.694 mg/mL Calculation of mass of CoSO4: Mass=1.694 mg mL-1×25 mL=42.35 mg…
Q: A 30-mL portion of a solution containing Ca²+ and Mg2+ was titrated with 28.19 mL of 0.207 M EDTA at…
A: Given that, In the first titration Volume of Ca-Mg solution = 30 mL Volume of EDTA used = 28.19 mL…
Q: 11. A solution of 0.0500M Ca²* and 0.00500M Mg* was titrated against EDTA at pH = 10 (K'r for CaY2…
A: EDTA is ethylenediaminetetraacetic acid which is an indicator. It has 2 amino and 4 carboxyl groups.…
Q: solution was prepared by dissolving about 3.0 g of NaH2Y2·2H2O in approximately 1 L of water and…
A: At equivalence point, V1× S1 = V2 × S2 Where V1 and V2 are the initial and final volume…
Q: A cyanide solution with a volume of 13.87 mL was treated with 24.00 mL of Ni+ solution (containing…
A: Concentration of CN- can be determined from the amount of Ni2+ used in the titration of CN-.
Q: Calculate the pZn2+ for solutions prepared by adding 0.00, 5.00, 10.00, 15.00, 20.00, 25.00 and…
A: Note - Since you have posted a question with multiple sub-parts, we will solve first three…
Q: using a buffer at pH 3.0, calculate the concentration of Ni2+ in a solution that was prepared by…
A: i)
Q: chip sample) is analyzed using EDTA titration with EBT as indicator. The following data were…
A:
Q: In a solution kept constant by buffering to pH= 8.0, 50.0 mL of 0.0050M Ni2+ is 0,0100 In titration…
A: The question is based on the concept of complexometric titrations. We have to calculate pNi at…
Q: *SHOW COMPLETE SOLUTION* A 4.971g sample containing the mineral tellurite was dissolved and then…
A: Solution - According to the question - Given - 3TeO2 + Cr2O72- + 8H+ ---> 3H2TeO4 + 2 Cr3+ + H2O…
Q: Calculate pMn² when 50.00 mL of 0,100 0 M Mn² is titrated with 25.00 mL of 0.200 0 M EDTA. The…
A: Given: 50.00 mL of 0.1000 M Mn2+ is titrated with 25.00 mL of 0.2000 M EDTA Kf = 7.76 × 1013 α =…
Q: A water sample was tested for hardness. To titrate Ca2* and Mg2+, a 25.00-mL sample needed 7.39 ml…
A:
Q: In the titration of MgSO4.2H2O (2g per litre) against a 0.01 M solution of the disodium salt of…
A: Given 0.01 M solution of EDTA the reaction involving titration of MgSO4.2H2O and EDTA can be…
Q: Given the following data during the potentiometric titration of 75.00 mL unknown NaCl solution by…
A:
Q: You are asked to titrate a Mn3+ solution with EDTA at pH 9.00. The overall ionic strength of the…
A: Solution- Log k = 25.2k =1025.2 nowαEDTA4−=5.4 ×10−2×1025.2 at pH=9(a) k'(conditional formation…
Q: What is the value of pMg for 50.0 ml of a 0.0500 M Mg2 solution buffered at pH 10.00 and titrated…
A: Magnesium ions react with EDTA to form magnesium EDTA complex. we have to calculate P value of…
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 3 images
- What is the value of pMg for 50.0 ml of a 0.0500 M Mg*2 solution buffered at pH 10.00 and titrated with 0.0500 m ED TA when 50.0 mL of EDTA is added (Kf = 6.2x108)(ay4. = 0.30 )? 1. O5.77 2. O2.88 3. 4.94 4. 1.39 5. 07.96What is the Ph of the buffer solution that contains 1.00 M HC2H302 (acid) and 0.800 M KC2H302 with pKa of 4.74?(7 What is the value of pMg for 50.0 ml of a 0.0500 M Mg*2 solution buffered at pH l10.00 and titrated with 0.0500 m EDTA when 51.0 mL of EDTA is added (Kf = 6.2x108) (ay4. = 0.30 )? 1. O2.88 2. 04.94 3. 06.57 4. 01.39 5. 07.96
- A 0.5131-g sample containing KBr is dissolved in 50 mL distilled water. Titrating with 0.04614 M AgNO3 requires 25.13 mL to reach the Mohr endpoint. A blank titration requires 0.65 mL to reach the same endpoint. Report the % (w/w) KBr in the sample. [Ans. 26.19 % (w /w)]What is the molar solubility of Ag2CO3 in an aqueous solution that is buffered to a pH of 2.37? Relevant constants: Ksp for Ag2CO3 = 8.1 x 10-12; K1 H2CO3 = 4.45x10-7; K2 for HCO3- = 4.69x10-11; Kw = 1.00x10-14.A 0.5264-g sample containing KBr is dissolved in 50 mL distilled water. Titrating with 0.04738 M AgNO3 requires 24.57 mL to reach the Mohr endpoint. A blank titration requires 0.75 mL to reach the same endpoint. Report the % (w/w) KBr (MM = 119.0) in the sample. 51.02 % 26.19% 12.76 % 25.51 %
- Direct titration: 10.90 ± 0.02 mL of an unknown KHP solution required 11.72 ± 0.02 mL of 0.1090 ± 0.0006 M NaOH to reach the end point. What is the concentration of KHP in the unknown solution reported with absolute uncertainty? If the unknown solution was prepared by dissolving 5.128 g of the unknown KHP (204.22 g/mol) in 100.00 mL of water, what is the weight percent of KHP in the sample?5. A 300.0 mg sample containing Na,CO3, NaHCO, and NaOH and inert material either alone or in some combination was dissolved and titrated with 0.1000 M HCI the titration required 24.41 ml to reach the phenolphthalein endpoint. And an additional 8.67 mL to reach the methyl red endpoint. Determine the composition of the sample and calculate the percent of each titrated component.A 270.00 mL solution of 0.00150 M AB4 is added to a 380.00 mL solution of 0.00250 M C3D4. What is pQsp for A3D4?
- Titration of the I2 produced from 0.2242 g of primary standard KIO3 required 34.95 mL of sodium thiosulfate (Na2S2O3). 103 + 51- + 6H* 312 + 3H20 12 + 2S2032- 21- S4062- + MM KIO3: 214.00 MM Na2S203: 158.11 Calculate the molar concentration of Na2S203.In the titration of MgSO4.2H2O (2g per litre) against a 0.01 M solution of the disodium salt of ethylenediamine tetraacetic acid (EDTA) the titres obtained were as follows ; titre 1: start - 0.7 ml and end - 13.3 ml (12.6ml) titre 2: start - 13.3 ml and end 25.7 ml (12.4ml) The average titre is 12.5ml Q. Calculate, based on the average titre of the accurate titres, the percentage of magnesium in the magnesium saltWhat is the value of [Mg2+] and pMg for 20.0 mL of a 0.020 M Mg²+ solution buffered at pH 10.00 and titrated with 0.020 M EDTA. K₁= 6.2 x 108 and CY4- at pH 10.0 = 0.30 a- when 5.0 mL of EDTA is added? b- when 20.0 mL of EDTA is added? c- when 25.0 mL of EDTA is added?