One problem which contains 3 parts, a , b and c We wish to produce a 1050 steel that has a Brinell hardness of at least 330 and elongation ofat least 15%.Strength (psi)a. Recommend a heat treatment, including appropriate temperature, that permits this tobe achieved. Determine the yield strength and tensile strength that are obtained bythis heat treatment.b. What yield strength would be obtained in a 1080 steel using the same heat treatmentprocess?c. What yield strength, tensile strength and % elongation would be obtained in the 1050steel it were normalized?200,000- Tensile100,000-YieldRockwellC hardnessTempering temperature (°C)Tensile strength (psi)Effect of tempering temperature onthe properties of a eutectoid steel.300,000200 400 600 800200,000Figure 1100,000200M₂k7060Bainite5040302010Rockwell C hardness% ElongationNoseTensile strengthYield and tensile strength (ksi)16014012010080300 400 500 600 700Transformation temperature (°C)6040EutectoidPearlite0Figure 220% ElongationImpact energy30Tensilestrength20100800Normalized-I0.2 0.4 0.6Weight percent carbonThe effect of carbon and heattreatment on the properties of plaincarbon steels.Normalized% ElongationAnnealedNormalized0.8100AnnealedYield strength 40AnnealedThe effect oftransformationtemperature on theproperties of a eutectoidsteel.8060201.0% Elongation or impact energy (ft lb)

We wish to produce a 1050 steel that has a Brinell hardness of at least 330 and elongation of at least 15%. a. Recommend a heat treatment, including appropriate temperature, that permits this to be achieved. Determine the yield strength and tensile strength that are obtained by this heat treatment. b. What yield strength would be obtained in a 1080 steel using the same heat treatment process? c. What yield strength, tensile strength and % elongation would be obtained in the 1050 steel it were normalized?

We wish to produce a 1050 steel that has a Brinell hardness of at least 330 and elongation of at least 15%. a. Recommend a heat treatment, including appropriate temperature, that permits this to be achieved. Determine the yield strength and tensile strength that are obtained by this heat treatment. b. What yield strength would be obtained in a 1080 steel using the same heat treatment process? c. What yield strength, tensile strength and % elongation would be obtained in the 1050 steel it were normalized?

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

(c) An annealed AISI 4340 steel was determine to have a Brinell hardness of HB = 216. Estimate %3D the tensile strength of this steel in MPa.
A shear pin made from a 4340 steel (0.4% C) fails by ductile fracture. It was supposed to be initially normalised, austenitised, quenched and tempered to 100% martensite to give a hardness of 5.5 GPa. The hardness was measured to be 4.5 GPa. Which of the following summaries most accurately accounts for what may have gone wrong? O Insufficiently heating the steel would result in partial austenitisation, leading to only partial martensite after quenching and a reduction in final hardness. The temper could still occur at the correct conditions and still lead to an insufficient strength and encouraging ductile failure. O Performing a full austenitisation but then cooling slower than the critical cooling rate for the alloy would allow some ferrite/pearlite to form after the martensite reaction has finished. This would be softer than the tempered martensite and so reduce the final hardness. O Assuming a full austenitisation and then cooling faster than the critical cooling rate, the hardness…
4340 steel has been selected to create a high-strength turbopump shaft. The diameter of the shaft is 1.75in. Suggest an overall processing sequence which includes steps such as raw material procurement , heat treatment, rough machining, and finish machining. Specify the heat treatment state the steel should be procured in. Suggest a heat treatment procedure to achieve a very high strength and hardness around 50 HRC. Specify the relevant AMS specification. Be sure to supply temperatures, soak times and quenchants as applicable.
An application requires ultimate tensile strength and yield strength ofa steel at 110 ksi and 91 ksi, respectively. Answer the following 4 questions: Can SAE 1040 steel be selected for this application? If “no” is the answer in Part I, the following Part II, III, and IV can beignored. If “yes” is the answer in Part I, which condition of SAE 1040 shouldbe selected? Why is that steel with the condition in part II selected? Is the selected steel brittle or ductile? and Why?
Austentitic stainless steel's are not hardenable by cold working however Austentic stainless steel's can be strengthened by heat treatment true or false?
c). Interpret the following diagram? The effect of carbon and heat treatment on the properties of plain carbon steels. 160 140 Tensile 120 strength, 100 Impact energy 100 Annealed 80 80 Normalized 60 60 Annealed 40 `Yield strength 40 20-% Elongation Annealed 20 Normalized< 0.2 0.4 0.6 0.8 1.0 Weight percent carbon Figure-4 Yield and tensile strength (ksi) Normalized % Elongation or impact energy (It • Ib)
Determine the yield strength sy and the ultimate strength su of the A36 steel either from Materials Science class book/notes, or by researching over the internet.
part made from AISI 1212 steel undergoes a 20 percent cold-work operation. (a) Obtain the yield strength and ultimate strength before and after the cold-work operation. Determine the percent increase in each strength. (b) Determine the ratios of ultimate strength to yield strength before and after the cold work operation. What does the result indicate about the change of ductility of the part?
Three separate heat treatments were applied to Ç1040 steel as quenching, quenching + tempering and softening annealing. Can you explain the modulus of elasticity, yield strength, toughness and resilience in a cause and effect relationship by showing the bottom tensile curves in each case of the samples on the same diagram?
2. Which property of this steel is significant to the failure analysis? The steel can Options: a. form carbides that strength it b. be heat treated in order to improve its strength. c. be strain-hardened.
Q1: Austenitized 40 mm diameter 5140 alloy steel bar is quenched in agitated oil. Predict what is the Rockwell hardness of this bar will be at (a) its surface and (b) its center (c) What do you think about the difference in hardness number between the center and surface (d) Differentiate between hardness and hardenability (e) Rank the steels in the figure below from lowest to highest hardenability and explain why. 600- Bar diameter (mm) 100 80 60 40 20 0 300 0 Cooling rate at 700°C (°C/sec). -150 55 0 تنا 25 ------- 5 S 10 12.5 8 M-R L 1/2 34-R Agitated oil 15 20 ¼ ¾ Distance from quenched end. De (Jominy distance) 5,5 54 Car Bar diameter (in.) 0 25 mm. 1 in. Hardness (Rockwell C) Where (C = center, S = surface, M-R = mid-radius) 2828 292 65 60- 55- 50 45 40 35 30 25 20 15 10 0 J 10 5140 30 20 Distance from quenched end (mm) 4340 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 Distance from quenched end (sixteenths of an inch) 40 9840 4140 8640 50
3000 kg, 10mm Steel Ball Brinell Hardness Reading of 421 is equal to what Rockwell C Reading?