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- Activity 3b - Diffusion across a semipermeable membrane 1. Define selective permeability. 2. Explain the properties of the cell membrane that make it selectively permeable. Activity 3c - Osmosis in potatoes 1. Define osmosis. 2. Define hypertonic, hypotonic, and isotonic. Hypertonic Hypotonic Isotonic Activity 3d - Osmosis in plant cells 1. Fill in the table below to indicate what happened to the elodea cells in each of the following solutions. Solution Hypertonic Isotonic Hypotonic Will the cell membrane swell or shrivel? What happens to the chloroplasts in the hypotonic solution? Why do you think that happens?Question:- Based on the figure below, predict what peptide bond could be the substrate of each protease(The bond marked in blue is where hydrolysis occurs, choose 2 peptides per protease type) Chymotrypsin:_________ Trypsin:_________ Elastase:_________ 1. SR−SG 2. SF−SG 3. SK−SG 4. SA−SG 5. SV−SG 6. SM−SGPlease explain!!! select all that are right the same Protein X was purified from tissue source A and tissue source B, yielding the following results: Protein X, sample A: specific activity = 100 U/mg; fold-purification = 200 Protein X, sample B: specific activity = 1000 U/mg; fold-purification = 100 Which of the following statements are correct? a) Protein X, sample A has a higher level of purity than Protein X, sample B. b) Protein X, sample B has a higher level of purity than Protein X, sample A. c) Tissue source A has a higher specific activity for Protein X than tissue source B. d) Tissue source B has a higher specific activity for Protein X than tissue source A.
- Hi need help on this one. I need a solution for each ! Thank you ----------------------------------------------------- (e.g 200 glucose x 36 ATP =7200 ATP) 1. If there is 1944 ATP produced, how many glucose molecules were broken down? 2. 20 glucose molecules were processed, how many net ATP molecules can be produced? • A. In Glycolysis • B. In Krebs Cycle: • C. In Oxidative Phosphorylation: • D. Total net ATP yield:Short Answer. Please answer the in a semtace or less. As discussed in lecture, after the death of a certain type of bacteria, patients suffering from a bacterial infection may demonstrate an increase of symptoms. These symptoms are due to a release of particular 1) Name the specific chemical component that can cause this worsening of symptoms in our pateient? 2) Where is this chemical normally found? (Name the specific anatomical part) 3) What type of bacteria produce this chemical? 4) Name the antigenic portion of the overall structural component. EC: 5) Name the molecule that this is a part of. (+1) Click Save and Submit to save and submit. Click Save All Answers to save all answers. 30°F Mostly cloudy O Search 2 Save All Answers Save and SubmitHBY-BIO-U2-TEST BIOCHEMISTRY-SY 20-21 Which statement BEST explains why enzymes bind to specific substrates? O Anenryme can be inibted se ds active site is altered An enzyme faids ditterently in the presence of diferent substrates O Diferert amino acd seguences cause variations in the shapes of an enzymes active sites O Enzymesubstrate binding is based on sze so ony large enrymes can bind to large ubstrates
- O Bio Test 1 Flash [Answer] 10. Al G Grammarly Mai 217ie/content/2484180/viewContent/46984558/View ps plecules of Life Don Sellers: Attempt 1 Listen Glucose is stored for short periods of time, primarily in the cells of the: liver and muscles. brain and liver. liver and spleen. muscles and pancreas. pancreas and liver. Question 8 (1 point) )Listen Why is it common for people to have dramatic weight loss when they first st Their heavy fat molecules are immediately depleted, causing them to lo uhich alone weigh quAnalysis of a protein is taking place. The enzymic acivity of this protein is stable up to temperatures of 40 degrees celsius. ph values are between 2.5 and 11.5. Now, Ion exchange chromatography is conducted via a software using DEAE-cellulose and method of elution is done by salt gradient. pH is set to 7. In terms of Molar, start of gradient is 0 and end of gradient is 1. The following graph is generated. Using the graph and analytical methods, determine pI of protein.BIOMOLECULES - Please answer the questions properly. - Multiple choice Allopurinol is an inhibitor of xanthine oxidase. Administration of allopurinol to a patient with gout and normal HG-PRT levels would be expected to lead to all of the following EXCEPT: A. decreased de novo synthesis of IMP B. increased xanthine in the blood C. increased levels of PRPP D. decreased urate in the urine 2. Which of the following unique attributes creates a steroid? A. 1 carboxyl group B. 4-fused carbon rings C. 2-fused oxygen molecules D. 3-fused hydrogen chains
- in human 2. Human xanthine oxidase catalyzes the oxidation of hypoxanthine to xanthine and can further catalyze the oxidation of xanthine to uric acid. For the treatment of hyperuricemia and gout. several medications are used to inhibit the activity of xanthine oxidase and reduce the production of uric acid. You are a biochemist and just discovered a chemical that can inhibit the activity of the human xanthine oxidase. When analyzing its mode of inhibition, you found that the enzyme inhibitor complex requires 450 kJ.mol to dissociate and that it displays kinetics somehow similar to noncompetitive inhibition. You sent your inhibitor to the ministry of health for approval as a medication for gout. Based on the data provided, are they going to authorize it as a medication or not? Explain?Question:- name the enzyme that is used in this reaction and explain whyTube # 2c Table 3-Determination of the optimum temperature of catechol oxidase enzyme. 1st Absorbance 0 min. at Expt. Temp. 3c 4c Q12) After 10 min at experimental temperature was enzyme activity high or low at 75°C and 100°C? Support your answer by looking at the difference between 2nd and 1st absorbances. ( 5c Q13) Was the enzyme denatured at 75°C and/or 100°C% Support your answer by looking at what happens after returning enzyme to room temperature AFTER enzyme was subjected to experimental temperatures of 20 °C,40 °C,60 °C,80 °C and 100°C. "¹ /1 Q14) What happens to the enzyme structure and function when it becomes denatured? ( Potato Expt. extract Temp. (mL) 2 2 2 2 room temp 20 °C 40 °C 75 °C Boiling 100 °C dH₂O Catechol (mL) (mL) 0 0 0 0 13 || 13 13 13 Start Time: 4:20 Absorbance: 0.072 Start Time: 4:25 Absorbance: 0.114 Start Time: 4:25 Absorbance: 0.132 Start Time: 4:27 Absorbance: 0.097 2nd Absorbance after 10 min. in Expt Temp. Time for reading: 4:30 Absorbance: 0.128 Time…