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Solved in 2 steps
- 1 Point Question 45 Identify the sequence of curved arrows (electron movementinthe steps of the following reaction. HS OgH lass of leaving group, carbocation rearrangement, nucleophilicattack oss of leaving group, nucleophilic attack, nucleophilic attack (C) loss of leaving group, proton transfer, nucleophilic attack D lossiof leaving group, loss of leaving group, nucleophilic attackis the indicated carbon electrophilic or nucleophilicWhich of the following is the MAJOR product of the following reaction? ... NaOEt ELOH Br ... (A OEt
- Which of the following is a stronger nucleophile in a polar, protic solvent? OF O HSWhat is the nucleophile and electrophile?027 In Part 1 add the curved arrows to the nucleophilic acyl substitution reaction mechanism. In Part 2, answer the multiple-choice question about the reaction in Part 1. Part 1 4 See Periodic Table O See Hint :0: :Br: Add the missing curved arrow notation. S CI Br Part 2 Which statement is most correct regarding the equilibrium for the above reaction? Choose one: O The equilibrium favors the right (i.e., Kea > 1) because acetate is a better leaving group than bromide. O The equilibrium favors the right (i.e., Kea > 1) because bromide is a better leaving group than acetate. O The equilibrium favors the left (i.e., Keq« 1) because acetate is a better leaving group than bromide. O The equilibrium favors the left (i.e., Keg 1) because bromide is a better leaving group than acetate. +
- Draw the resonace strutures of methoxy benzere. what is the resonancediffrentiate betwwen strong nucleophile and mild nucleophile.In Part 1 add the curved arrows to the nucleophilic acyl substitution reaction mechanism. In Part 2, answer the multiple-choice question about the reaction in Part 1. Part 1 See Periodic Table O See Hint :ö: :Br: Add the missing curved arrow notation. 20 F CI Br I Part 2 Which statement is most correct regarding the equilibrium for the above reaction? Choose one: O The equilibrium favors the right (i.e., Kea > 1) because acetate is a better leaving group than bromide. O The equilibrium favors the right (i.e., Keg > 1) because bromide is a better leaving group than acetate. O The equilibrium favors the left (i.e. Keg « 1) because acetate is a better leaving group than bromide. O The equilibrium favors the left (i.e., Keg« 1) because bromide is a better leaving group than acetate.