ver you online tutórs! Try bartleby ti Step 2 3yt+13y +4 =D0 3y2+12y+y+4 = 0 3y(y+4) +1Ly+4) = 0 (4+4) (3y+1) = 0 +) =0 ニ 3. 80 the valus of 平=R d are -4,3

Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter6: Quadratic Equations And Inequalities
Section6.S: Summary
Problem 10S
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i cant follow. how did the three get to the outside? why did the 12y get split up? how did there become a +1? why are there two sets of 4 now? 

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Step 2
Sy+13y +4 =0
3y2+12y+y+4 = 0
34(4+4)+14+4) = 0
(y+4) (3y+1) = 0
Y+4 =0 , 3y
hー=&
3y = -1
-4=D0
+) =0
%3D
%31
8o the valus of y are
-4,
ロ
Transcribed Image Text:bartleby.com = bartleby Q Search for textbooks, step-by-step explanations to homework question e Q&A Library Find all real solutions of the equation by factori.. Get live help whenever you need from online tutors! Try bartleby tut Step 2 Sy+13y +4 =0 3y2+12y+y+4 = 0 34(4+4)+14+4) = 0 (y+4) (3y+1) = 0 Y+4 =0 , 3y hー=& 3y = -1 -4=D0 +) =0 %3D %31 8o the valus of y are -4, ロ
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