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- TEST ACTIVITY #5: DIRECT CURRENT CIRCUITS Name: Score: Section: Date: PROBLEM 2: Three resistors of 25 N, 30 N and an unknown resistance R are connected in parallel and the combination is connected to a 16 V source. If the total current delivered by the source is 1.5 A, | determine the following: A. The value of R. B. The current in each resistor. C. Which resistor dissipates the highest power? Show your solution. Based on your answer, what conclusion can be made? SOLUTION:QUESTION 2 A simple series circuit of R1 and R2 connected to a 12 VDC source. A voltmeter on a 5 V range is connected to measure the voltage across R2. The value of each resistor R1 = 70 kN and R2= 50 kN in the circuit. a) Find the voltage across R2, VR2 if the voltmeter is set as follows. i. without the meter connected ii. with a voltmeter having a sensitivity of 20 k2/V iii. with a voltmeter having a sensitivity of 200 k2/V b) Find which voltmeter will read the accurate value of voltage across R2. Justify your answer.Extra 1. Model the "RC-circuit" and find the current in the circuit fom (1) a constant electromotive force E(t)= E, and (2) a periodic electromotive force E(t) = E, sin(axr). Note. E, RI and E , ==S Idt. E(t)
- QUESTION 3 Suppose that you have a leaf blower that draws 1100 Watts in operation, It is fed by an extension cord that is plugged into a 120 volt outlet by two wires having a resistance of 0.15 ohms each. Because of that resistance, the voltage at the leaf blower is a bit less than 120 volts, but you can stll assume that it runs on the same current it would if it were connected to a true 120 volt supply. How much power is dissipated in the extension cord? 25 watts 13 watts O 40 watts 63 watts O 20 wattszV9 @ Ooredoo lI. 10 4 Not yet answered Marked out of 2.00 P Flag question for the circuit below. R1=32, R2=42, and the potential difference of the battery is 15V R1 R2 i) Calculate the equivalent resistance of the circuit ( in Ω) ii) total current across the circuit. Finish attempt ... 1 Pro Ouest Link for Tonic 4 Work Enerav Powe. moodle.nct.edu.om AProblem 2 A nuclear power plant produces on average 600 MW, the voltage transmission lines operate at 345 kV. The transmission lines are made out of aluminum with a resistivity of 2.83x10-8N m. Assume the crosssectional area of the wire is 600 mm2 Measure the energy loss associated with transmission of 100 miles? Assuming that each house on average consumes 1.3 kW, how many houses of power are lost in transmission? Pe =
- Problem #5 Vi= 10V a R1 = 2ohms. R45ohms ww R3 = 7ohms ww W Figure P5 Wheatstone Bridge Circuit R2 = 3ohms: ww R560hms b Solve the current flowing R1, R2, R3, R4, and R5 shown in figure P5, using KVL and KCLSecond graph The V vs t graph shown below is for the resistor of an RC circuit. V (V) 10 7.5 5. 2.5 1.5 3. 4.5 6. 7.5 t(s) Determine the time constant of the RC circuit. T= If C = 3 F, determine R. R= Ω In this case, was the capacitor charging or discharging? impossible to determine impossible to determinelyah Active Now АСTIVITY SHEET 3&4 April 5,2022-April 6, 2022 DIRECTIONS: Solve the following given problems with complete solutions and answers. 1. A 20.0 ohm resistor is connected in parallel with a 5.0 ohm resistor, with a 50.0 V across the combination. Find (a.) voltage across each resistor, (b) current passing through each resistor, and (c) total current passing through the combination. Repeat (a),(b),(c)but this time the resistors are in series. 2. The parallel combination of 40 ohms, 60 ohms and 120 ohms is connected in series with a 15 ohm and 25 ohm resistors. The whole network of resistors is connected to a 120 V line. Determine (a)total current, (b) current passing through the 15 ohms resistor, (c) the potential drop across the parallel group of resistors,(d) the voltage across the 40 ohms and (c) the current through the 120 V resistors. More Edit II :
- 2. The Voltmeter connected across the resistor will measure [Choose any one answer] 3. A constant current source supplies a electric current of 200 mA to a load of 2kQ. When the load changed to 500, the load current will be O8A O9mA O12A 0700mA 4. To measure the resistance, the knob should be at E 5. Which of the following a correct statement for the resistors R1, R2 and R3? R1 R2 I (ampere) R3 V(volts)LEARN MORE Remarks A common misconception is that the current is "used up" and steadily declines as it progresses through a series of resistors. That would be a violation of conservation of charge. What is actually used up is the electric potential energy of the charge carriers, some of which is delivered to each resistor. Question Explain why the current in a real circuit very slowly decreases with time compared to its initial value. As current flows in the circuit, electrons leave the negative terminal and other electrons reach the positive terminal. The potential difference across the circuit gradually declines, and so the current decreases. As current flows in the circuit, the resistance of the resistors outside the battery gradually increases. This raises the equivalent resistance of the circuit, and the current gradually decreases. As current flows in the circuit, the internal resistance of the battery increases over time. This raises the equivalent resistance of the circuit, and…Shown in the figure below is an electrical circuit containing three resistors and two batteries. R₁ ww 1₁₂₁ 10 0= R₂ R3 www Write down the Kirchhoff Junction equation and solve it for Is in terms of 12 and 13. Write the result here: Write down the Kirchhoff Loop equation for a loop that starts at the lower left corner and follows the perimeter of the circuit diagram clockwise. 13 Write down the Kirchhoff Loop equation for a loop that starts at the lower left corner and touches the components 10V, R₁, 4V, and R₂. The resistors in the circuit have the following values: R₁-20 • R₂=60 Rg 110 Amperes Amperes Amperes Solve for all the following (some answers may be negative): 11 = 12 = 13= NOTE: For the equations, put in resistances and currents SYMBOLICALLY using variables like R₁, R₂,R3 and 11.12.13. Use numerical values of 10 and 4 for the voltages.