Using the alternate form of newtons second law, compute the force (in N) needed to accelerate a 1,160 kg car from 0 to 23 m/s in 12s. The change in momentum is the car's momentum when traveling 23 m/s minus its momentum when going 0 m/s. ( enter the magnitude)

Using the alternate form of newtons second law, compute the force (in N) needed to accelerate a 1,160 kg car from 0 to 23 m/s in 12s. The change in momentum is the car's momentum when traveling 23 m/s minus its momentum when going 0 m/s. ( enter the magnitude)

Name: Using the alternate form of newtons second law, compute the force (in
Uploaded: 2024-03-20T06:57:37.000Z
Channel: Bartleby
Description: Using the alternate form of newtons second law, compute the force (in N) needed to accelerate a 1,160 kg car from 0 to 23 m/s in 12s. The change in momentum is the car's momentum when traveling 23 m/s minus its momentum when going 0 m/s. ( enter the

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter9: Linear Momentum And Collisions

Section: Chapter Questions

Problem 34P: A ball of mass 250 g is thrown with an initial velocity of 25 m/s at an angle of 30 with the...

See similar textbooks

Similar questions

A ball of mass 250 g is thrown with an initial velocity of 25 m/s at an angle of 30 with the horizontal direction. Ignore air resistance. What is the momentum of the ball after 0.2 s? (Do this problem by finding the components of the momentum first, and then constructing the magnitude and direction of the momentum vector from the components.)
A hockey puck of mass 150 g is sliding due east on a frictionless table with a speed of 10 m/s. Suddenly, a constant force of magnitude 5 N and direction due north is applied to the puck for 1.5 s. Find the north and east components of the momentum at the end of the 1.3-s interval.
please answer the following Using the alternate form of Newton's second law, compute the force (in N) needed to accelerate a 1,030 kg car from 0 to 23 m/s in 14 s. The change in momentum is the car's momentum when traveling 23 m/s minus its momentum when going 0 m/s. (Enter the magnitude.)
The kinetic energy of a particle of mass 0.200 kg is 320 J. Its momentum, in kg m/s, is (use one decimal in your answer):
what momentum does a car of mass 1,762 kg have if its traveling at 11.3 m/s? answer in exponential form.
A body has a momentum of 80 kg m/s and a kinetic energy of 275 J. Determine the mass of the body.
In Section 2.4, we computed the force needed to accelerate a 1,000-kg car from 0 to 27 m/s in 10 s. Compute the force using the alternate form of Newton's 2nd law. The change in momentum is the car's momentum when traveling 27 m/s minus its momentum when going 0 m/s.
9.1 x 10-31 kg) is accelerated from rest to a speed of 2 x 108 Extra: An electron (mass : m/s in 1 second. (a) What is the momentum of the electron when it has reached this speed? (b) What was the average force needed to accelerate the electron to this speed? (c) Suppose the same force as in (b) continues to act on the electron, how fast will it be 0.5 s later? (What, if anything, can you conclude from your results? Do they make sense?)
For how long should a force of 52 N be applied to change the momentum of an object by 9 kg.m/s?
A car of mass 600 Kg is moving with a velocity of 10 m/s. Determine its Momentum.
What is the mass of a mallard duck whose speed is 8.8 m/s and whose momentum has a magnitude of 12 kg*m/s?
What is the momentum of a car (m=800kg) that is moving at 35 mph? (use the referents kg*m/s)