Using superposition, determine the current through the 802 resistor for the network below E₁ = 10 V 20° + E₂ = 4V 180'with E2 shorted = 180" with E1 shorted = 180= R₁ Xc www 26Ω HE HI 5202 2 XL m 4 Ω R₂ * 8 Ω units units units

Using superposition, determine the current through the 802 resistor for the network below E₁ = 10 V 20° + E₂ = 4V 180'with E2 shorted = 180" with E1 shorted = 180= R₁ Xc www 26Ω HE HI 5202 2 XL m 4 Ω R₂ * 8 Ω units units units

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter6: Power Flows

Section: Chapter Questions

Problem 6.61P

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Concept explainers

Current Division Method

The generalized current divider formula is given by the following relation below,

Question

Using superposition, determine the current through the 80 resistor for the network below
E₁ = 10 V 20°
E₂ = 4 V
180' with E2 shorted
180"with E1 shorted
180 =
||
+
=
+
R₁
Xc
2
+
6Ω
222
2
2
XL
moo
4Ω
R₂
O
8 Ω
units
O
O
units
units

Using superposition, determine the current through the inductance XL for the network below
E₁
XL
IL:
= 20 VZ0°
L'with E2 shorted & I opened
=
ell
IL" with E1 shorted & I opened
IL"with E1 shorted & E2 shorted
=
3 Ω R 1Ω
+
N
E2 = 120 V Z 0°
V
2
2
O
I = 0.5 AZ 60°
units
O
units
units
° units

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