Using an appropriate substitution, ſ tan³(x)sec"(x)dx is equal

Q: y = 3 sin 3X tan 2x

A:

Q: Find and simplify the second derivative of f(0) = cos(sin(30))

A:

Q: y = cos*x – sin*x

A: y = cos 4 x -  sin 4 x

Q: Find [10] -t sin(v3t) е (а) L (b) L-- [tan-1 ))

A: We have to solve given problem:

Q: 2. y = (cosx)(sin5x)

A: We will use product rule of differentiation to find the first derivative of this function. We will…

Q: Using appropriate substitution, S [sec³ (2x) – 2] tan(2x) dx is equal to

A: integration

Q: 10. Find the derivative of y = cos /sin(tan 7x)

A: We will find the derivative using Chain rule

Q: Use the General Power Rule, Exponential Rule, or the Chain Rule to compute the derivative. y = (2…

A: Given function is   Differentiating both sides with respect to x, we get

Q: 4 x ) dx. 4 tan x

A: topic - definite integral using integration properties

Q: find (y') by Implicit differentiation x² tan(y) + y10° sec(x) = 2x

A:

Q: Differentiate with respect to the independent variable: y=tan[ln(3x2+5)]

A:

Q: h(x)= cot r11- tan"x

A: Given, hx=cot-11x-tan-1x We have to find h'x.

Q: Find dy/dx of inverse tan(1/x) multiplied by secant(x)

A:

Q: f(x) = e2 sin¯+(3x) + In (cosh-1(e³x))

A:

Q: S tan' (2x)sec“ (2x) dx

A: “Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: Using appropriate substitution tan3. dx sec5x tan³x is equal to

A:

Q: Find the derivative of cos-¹(sin x)

A:

Q: S tan (2x)sec (2x)dx = %3D

A:

Q: Differentiate sin (x2 + x) with respect to x.

A: The given function is, y=sinx2+x. The objective is to differentiate the function y=sinx2+x with…

Q: Using appropriate substitution, f sin°(x)cos³ (x)dx is equal to:

A:

Q: Find the derivative.

A: Given     y=sin-1xcos-1xdydx=cos-1x ddx sin-1x-sin-1x ddx cos-1x ( cos-1x  )2       =cos-1x 11-x2…

Q: find (y') by Implicit differentiation x² tan(y) + y10 sec(x) = 2x

A: x2tan(y)+y10sec(x)=2xDifferentiate w.r.t x

Q: Compute Each Derivative: 1) d tan¯¹ (1 + e²x) dx 2) x²cos-¹(3x4) d dx 3) x(sin-¹(x))² dx

A:

Q: Using an appropriate substitution, S tan (x)sec (x)dx is equal to:

A: Given∫tan3(x)sec9(x)dx

Q: (Vian tan³ x + 1) sec" x dx

A:

Q: Which is the derivative (dy/dx) of y=sin-1 tanx?

A: Formula used   (fog)'(x) = f'(g(x))*g'(x)

Q: Differentiate sin(3x+5) with respect to x

A:

Q: find the derivative of f(x) = cos(sin(4x+7)^4). simplify

A:

Q: Q If find x tan cy2 of +2x the Value dx?

A: Given function is                                                  x2y+3y4=xtany+2x differentiating…

Q: Find the first derivative Complete Solution.  1.) t=sinθtanθ

A:

Q: Derive a formula for tan x sec" x dxr where n# 0.

A: Please go through the attached solution. I hope that this solution will help you. Thankyou . Best…

Q: find the first derivative: y=tan (x sin x)

A:

Q: Find y' of tan x = Sin y -2x5

A:

Q: How would you evaluate∫tan10 x sec2 x dx?

A: given ∫tan10 x sec2 x dx

Q: Find the 2nd derivatives

A:

Q: tan³ (In x) sec (In x) dx (8)

A:

Q: 3. Evaluate tan¹x² 1+x dx.

A:

Q: 1. ſ tan5 2x sec3 2x dx

A: Let,I=∫tan52xsec32xdxI=∫sin52xcos52x1cos32xdxI=∫sin52xcos82xdxI=∫sin42xcos82xsin(2x)dxusing…

Q: 19. Evaluate using u-substitution: S tan6x sec² x dx

A:

Q: y = In[cos? (3x)]

A:

Q: Find the first derivative y= tan2(sin x)

A:

Q: Find f"(x), where f(x) = tan-(sin x2019)

A:

Q: In Seln sin" x dx √√1-x

A:

Q: Find the derivative  h(x)= sin(tan 2x)

A: Given,

Q: Compute the derivative d tan x dx \cos x – 4)

A: To compute :

Q: Differentiate: y = (e2x)/(sin(2x))

A: We have to differentiate the function: y=e2xsin 2x Here two function are in ratio so we should use…

Q: Compute the derivative d tan x dx \cos x – 4

A: Given: Formula Used:

Q: Find the first derivative of the function y = In[tan (pi/4 + x/2)

A:

Q: B1. By using substitution method, evaluate [5 tan x sec² x dx.

A: To solve the given integral using substitution

Rate of Change

The relation between two quantities which displays how much greater one quantity is than another is called ratio.

Slope

The change in the vertical distances is known as the rise and the change in the horizontal distances is known as the run. So, the rise divided by run is nothing but a slope value. It is calculated with simple algebraic equations as: