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Use the tabulated electrode potentials to calculate K for the oxidation of zinc by H+ (at 25 ∘C): Zn(s)+2H+(aq)→Zn2+(aq)+H2(g)

Use the tabulated electrode potentials to calculate K for the oxidation of zinc by H+ (at 25 ∘C): Zn(s)+2H+(aq)→Zn2+(aq)+H2(g)

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter17: Electrochemistry And Its Applications
Section: Chapter Questions
Problem 38QRT
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Use the tabulated electrode potentials to calculate K for the oxidation of zinc by H+ (at 25 ∘C):

Zn(s)+2H+(aq)→Zn2+(aq)+H2(g)

Standard reduction half-cell potentials at 25° C E° ( V) E° Half-reaction Half-reaction |(V) Au? (aq) + Зе Au('s) 1.50 Fe2 (aq) + 2e-→Fe(s) 0.45 Ag+ (aq) +e→Ag(s) Cr3+ (aq) +e→Cr²+ (aq) 0.80 0.50 Fe+ (aq) + 3e→Fe?+ (aq) 0.77 Cr" (aq) + 3e-→Cr(s) 0.73 Cu+ (aq) + €¯→CU(s) Zn2+ (аq) + 2е —Zn(s) 0.52 0.76 Cu2+ (aq) + 2e →Cu(s) Mn2+ (aq) + 2e →Mn(s) 0.34 1.18 | 2H (aq) + 20→H2(g) 0.00 Al+ (aq) + 3e-→Al(s) 1.66 Fe (aq) + 3e–→Fe(s) Mg²+ (aq) + 2e–→Mg(s) 0.036 2.37 Pb2+ (aq) + 20→P6(s) Na+ (aq) + e¯→Na(s) 0.13 2.71 Sn²+ (aq) + 2e→Sn(s) Ca2+ (aq) + 2e→Ca(s) 0.14 2.76 Ni?+ (aq) + 2e →Ni(s) Bа? (аq) + 2е —Ba(s) 0.23 2.90 Co2+ (aq) + 20→C0(s) K* (aq) +e→K(s) 0.28 2.92 Cd2+ (aq) + 2e →Cd(s) Lit (aq) +E→Lİ(s) 0.40 3.04
Transcribed Image Text:Standard reduction half-cell potentials at 25° C E° ( V) E° Half-reaction Half-reaction |(V) Au? (aq) + Зе Au('s) 1.50 Fe2 (aq) + 2e-→Fe(s) 0.45 Ag+ (aq) +e→Ag(s) Cr3+ (aq) +e→Cr²+ (aq) 0.80 0.50 Fe+ (aq) + 3e→Fe?+ (aq) 0.77 Cr" (aq) + 3e-→Cr(s) 0.73 Cu+ (aq) + €¯→CU(s) Zn2+ (аq) + 2е —Zn(s) 0.52 0.76 Cu2+ (aq) + 2e →Cu(s) Mn2+ (aq) + 2e →Mn(s) 0.34 1.18 | 2H (aq) + 20→H2(g) 0.00 Al+ (aq) + 3e-→Al(s) 1.66 Fe (aq) + 3e–→Fe(s) Mg²+ (aq) + 2e–→Mg(s) 0.036 2.37 Pb2+ (aq) + 20→P6(s) Na+ (aq) + e¯→Na(s) 0.13 2.71 Sn²+ (aq) + 2e→Sn(s) Ca2+ (aq) + 2e→Ca(s) 0.14 2.76 Ni?+ (aq) + 2e →Ni(s) Bа? (аq) + 2е —Ba(s) 0.23 2.90 Co2+ (aq) + 20→C0(s) K* (aq) +e→K(s) 0.28 2.92 Cd2+ (aq) + 2e →Cd(s) Lit (aq) +E→Lİ(s) 0.40 3.04
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