Use the level pool method to route the inflow hydrograph given below. The storage-outflow characteristics are also given below. Use a time interval (time step) of 10 minutesin your calculations. Initially the storage is zero. Compute the outflow, and plot theinflow and outflow hydrographs in the same figure. Make sure to perform routing for atleast 6 hours.Storage (ft³)Discharge0 3267065340 98110130680 163350 196020051225303854(cfs)Storage (ft³)228690261360294030326700Discharge (cfs)90100120140Time (min)0102030405060708090Inflow (cfs)0152535353540556260Time (min)100110120130140150160170180190Inflow (cfs)504235302520151000Time (min)200210220230240200Inflow (cfs)000000

Step 1: For the level Pool reservoir, storage & outflow are unique functions of elevation in the…

Answered: Use the level pool method to route the…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Please provide complete solution. 1. Neglecting the losses, find the discharge through the venture meter. a. 0.0314 m^3/s b. 0.0404 m^3/s c. 0.0507 m^3/s d. 0.0870 m^3/s 2. Considering head loss between point 1 and 2 equal to 20% of point 1 velocity head, Calculate the rate of flow. a. 0.0210 m^3/s b. 0.0576 m^3/s c. 0.0401 m^3/s d. 0.0311 m^3/s
The hydraulic conductivity of a homogeneous gravelly aquifer is 3 x 10-1 cm/sec. The hydraulic gradient (groundwater surface slope) of the phreatic (water table) aquifer is 0.01 and the aquifer's effective porosity is 0.25. Calculate the following two parameters and provide the answer to question b) in the space provided (numerical answer only, no units or any). Calculate the specific discharge that represents flow conditions of the aquifer in cm/sec. Also Calculate the approximate average velocity of a conservative solute dissolved in this aquifer, calculated to units of cm/sec (enter numerical answer without stating units).
Question 2 Route the inflow hydrograph through a reservoir as indicated in Table 2. The crest height of the spillway is 50 ft and storage capacity at this level is 116 ft3/s-day. The reservoir routing curves graph is given in Figure 1. Perform calculation until the outflow value is equal to zero. Based on the obtained result, plot the inflow and outflow hydrographs. Table 2 0.4 1.6 2 2.4 2.8 Time (day) 0 Flow (ft³/s) 0 0.8 120 1.2 229 56 380 268 155 50 Figure 1 25/atO (ft/s.day)-primary x-axis 700 800 900 1000 54.0 53.5 53.0 52.5 52.0 51.5 Elevation vs Storage (curve a) Elevation vs 25/De-O (curve b) Elevation vs Outflow (curve c) 51.0 50.5 50.08 49.5 110 230 0 Water Surface Elevation (tt) 400 W 500 130 100 600 150 200 190 170 210 Storage (ft³/s.day) - secondary x-axis 300 400 500 Outflow (ft³/s.day) - tertiary x-axis 600 250 1100 700
1- There following data are obtained from streamflow measurement in a river cross section. Estimate the average discharge from this cross-section. Distance from the left corner (m) 0 Water depth (m) 0 Flow velocity at 0.2 d (m/s) 0 Flow velocity at 0.8 d (m/s) 0 1 1.35 0.6 0.7 0.2 0.3 2 3.31 3 4 5.0 9.0 0.85 1.0 0.5 0.6 6 5.38 3.78 0.8 0.7 0.6 0.4 55 7 1.78 0.6 0.3
(b) A simple reservoir has a linear storage indication curve defined by Q/2 = S/At, where At = 1.0 hr. If S at 8 A.M. is zero ft³/s-hr, use the continuity equation to route the following hydrograph through the reservoir. Time (hr) 9 A. M. 11 A. M. 12 Noon 120 Inflow (ft³/s) 65 110 8 A.M. 40 10 A. M. 80 1 P.M. 170
8.1 The storage, elevation and outflow data of a reservoir are given below: Outflow discharge (m³/s) Elevation (m) 299.50 300.20 300.70 301.20 301.70 302.20 302.70 Storage 10 m² 4.8 5.5 6.0 6.6 7.2 7.9 8.8 0 0 15 Time (h) 0 3 6 9 12 Discharge (m/s) 10 20 52 60 53 40 75 115 160 The spillway crest is at elevation 300.20 m. The following flood flow is expected into the reservoir. 15 18 21 24 27 43 32 22 16 10 If the reservoir surface is at elevation 300.00 m at the commencement of the inflow. route the flood to obtain (a) the outflow hydrograph and (b) the reservoir elevation vs time curve. 8.2 Solve Prob. 8.1 if the reservoir elevation at the start of the inflow hydrograph is at 301.50 m.
(a) Route the inflow hydrograph given below through a reservoir. The storage data (surface elevation versus storage volume) for the reservoir are also given below. The spillway discharge is expressed by the equation (Q = 3 LH2). The crest height of the spillway is 50 ft. and the length of the spillway is 35 ft. Inflow Hydrograph: Time (days) Inflow (ft/s) 0 70 185 360 0 0.5 1 1.5 |2 2.5 3.0 3.5 4.0 480 300 165 80 0 Storage Data: Elevation (ft.) Storage (acre-ft.) 50.0 50.5 51.0 51.5 52.0 52.5 53.0 53.5 231 247 277 313 353 400 452 509 (b) A simple reservoir has a linear storage indication curve defined by Q/2 =S/At, where At 1.0 hr. If S at 8 A.M. is zero f/s-hr, use the continuity equation to route the following hydrograph through the reservoir. Time (hr) Inflow (ft'/s) 8 A. M. 10 A. M. 80 11 A. M. 1 P.M. 9 А. М. 12 Noon 40 65 110 120 170
Design the in-line storage volume required to equalize the flowrate by using the following data. Provide a 25 percent excess capacity for equipment, unexpected flow variations, and solids accumulation Time (hour) Flow (m/s) 0000 0.0591 0200 0.0336 0400 0.0297 0600 0.0336 0800 0.0619 1000 0.0780 1200 0.0828 1400 0.0860 1600 0.0916 1800 0.0891 2000 0.0693 2200 0.0593
Question 7 (Parallel pipes) Two reservoirs are connected by two parallel pipelines with diameters of 0.8m and 0.6m as shown in Figure 8. The pipelines are both 3 km long with a value of 0.03. The combine discharge through the pipelines must be at least. Pipe 2 Pipe 1 Figure 8 a) When the total discharge is, what is the flow rate in the individual pipeline? b) What is the minimum difference in the elevation of the surface water level in the two reservoirs required to maintain a flow of through the pipelines?
Three reservoirs are connected in a common junction. Following are the pertinent information: Reservoir A: Elevation 90 m, 1800 m pipe with 400 mm diameter and f = 0.02 Reservoir B: Elevation 50 m, 2000 m pipe with 500 mm diameter and f = 0.025 Reservoir C: Elevation 10 m, 4000 m pipe with 800 mm diameter and f = 0.03 Determine the flow in each pipe. PLEASE INCLUDE COMPLETE DRAWING AND SOLUTION
The ordinates of a six-hour unit hydrograph for a catchment area of 1000 km2 are given below. Time (Days) Discharge (m^3/sec) 6 80 12 200 18 146 24 80 30 50 Separate the base flow using two methods: (Tabulate and Graph) a. Straight Line Method b. Fixed Base Method 36 15 42 0
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