up the equilibrium NH4+(aq) + OH-(aq) ⇌ NH3(aq) + H2O(l). Because both are acids, a buffer is formed. However, in the second case, NH3 is a base and OH– is an acid, so no buffer is possible.   b)  OH– is a weak base, and NH4+ is a strong base. They react with one another to form NH3, thereby setting up the equilibrium NH4+(aq) + OH-(aq) ⇌ NH3(aq) + H2O(l). Because both are bases, a buffer is formed. However, in the second case, NH3 is an acid and OH– is a base, so no buffer is possible.   c)  OH– is a base, and NH4+ is a strong acid. They react with one another to form NH3, thereby setting up the

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Chapter13: Acids And Bases
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Problem 99QAP: Each box represents an acid solution at equilibrium. Squares represent H+ ions. Circles represent...
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Why can a buffer be prepared from a mixture of NH4Cl and NaOH but not from NH3and NaOH?

 

Question 26 options:

 

a) 

OH is a weak base, and NH4+ is a strong base. They react with one another to form NH3, thereby setting up the equilibrium NH4+(aq) + OH-(aq) ⇌ NH3(aq) + H2O(l). Because both are acids, a buffer is formed. However, in the second case, NH3 is a base and OH is an acid, so no buffer is possible.

 

b) 

OH is a weak base, and NH4+ is a strong base. They react with one another to form NH3, thereby setting up the equilibrium NH4+(aq) + OH-(aq) ⇌ NH3(aq) + H2O(l). Because both are bases, a buffer is formed. However, in the second case, NH3 is an acid and OH is a base, so no buffer is possible.

 

c) 

OH is a base, and NH4+ is a strong acid. They react with one another to form NH3, thereby setting up the equilibrium NH4+(aq) + OH-(aq) ⇌ NH3(aq) + H2O(l). Because both the base (NH3) and the conjugate acid (NH4+) are present, a buffer is formed. However, in the second case, NH3 and OH are both acids, so no buffer is possible.

 

d) 

OH is a base, and NH4+ is a weak acid. They react with one another to form NH3, thereby setting up the equilibrium NH4+(aq) + OH-(aq) ⇌ NH3(aq) + H2O(l). Because both the base (NH3) and the conjugate acid (NH4+) are present, a buffer is formed. However, in the second case, NH3 and OH are both bases, so no buffer is possible.

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