ug the above info into Newton's law of cooling: (T=A+Be^kx) Write your answer as a time, not just as x minutes. Recall that when ,x=0, the time is 2:00 PM.   Question I: When forensic expert determines the time of death, they often have additional information besides body temperature. Suppose a coroner finds that the person who was murdered had an infection that probably raised the core body temperature to around 102 °F. Using the same cooling constant, ambient room temperature, and temperature data, make a new estimate for the time of death. Cooling constant is: -0.002564 Ambient Room temperature:  68         Again, write your answer as a time, not just as x minutes.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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PLEASE SOLVE THE FOLLOWING THREE QUESTIONS

Question G: Generally speaking, (no numbers required), at what point does Newton's Model of Cooling (T=A+Be^kx) (when regarding dead bodies' temperatures) no longer work? What in reality gives us an indication that we’ve taken it too far?

 

Question H: Assuming that the temperature of the person at the time of death (TOD) was 98.6 °F, set up a TOD equation using the values of ,A, ,B, and k you’ve calculated. Then, solve the equation using the same logarithm method you used to solve for .k.

A: 68 Farehneits, B: 17.9 Fareinheit

K: -0.002564

TOD: 98.6 Fareinheit 

Plug the above info into Newton's law of cooling: (T=A+Be^kx)

Write your answer as a time, not just as x minutes. Recall that when ,x=0, the time is 2:00 PM.

 

Question I: When forensic expert determines the time of death, they often have additional information besides body temperature. Suppose a coroner finds that the person who was murdered had an infection that probably raised the core body temperature to around 102 °F. Using the same cooling constant, ambient room temperature, and temperature data, make a new estimate for the time of death.

Cooling constant is: -0.002564

Ambient Room temperature:  68        

Again, write your answer as a time, not just as x minutes.

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