Two rods of equal length L = 1.40 m form a symmetric cross. The horizontal rod has a charge of Q = 500.00 C, and the vertical rod a charge of -Q = -500.00 C. The charges on both rods are distributed uniformly along their length. Calculate the potential at the point P at a distance x = 2.60 m from one end of the horizontal rod.

icon
Related questions
Question
Two rods of equal length L = 1.40 m form a symmetric cross. The horizontal rod has a
charge of Q = 500.00 C, and the vertical rod a charge of -Q = -500.00 C. The charges on
both rods are distributed uniformly along their length. Calculate the potential at the point P
at a distance x = 2.60 m from one end of the horizontal rod.
Transcribed Image Text:Two rods of equal length L = 1.40 m form a symmetric cross. The horizontal rod has a charge of Q = 500.00 C, and the vertical rod a charge of -Q = -500.00 C. The charges on both rods are distributed uniformly along their length. Calculate the potential at the point P at a distance x = 2.60 m from one end of the horizontal rod.
Expert Solution
steps

Step by step

Solved in 6 steps with 6 images

Blurred answer