TRANSCRIBE THE FOLLOWING TEXT IN DIGITAL FORMAT
Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)
10th Edition
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Russell E. Smith
Chapter7: Alternating Current, Power Distribution, And Voltage Systems
Section: Chapter Questions
Problem 7RQ
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Question
TRANSCRIBE THE FOLLOWING TEXT IN DIGITAL FORMAT
![So line currents
IR = √3 | Jph | = 72.015 Amp L-36
Reactive
Sey = √5 $ phl = 42.05/-156.86 Amp
1/83. 14 Amp
IB
(P) Real (or) ture
w
complex power
power
P
power
72.05
=
* = √3 V₂ IL cosø
= √3 x 208 x 72.05 cos (36.86)
20768.455 watts.
N
= √3 Y₂ IL Sinds
(@=
25957. 20622 x0.6
15574.32
(20768.455
-36.86*
cost=
Cost =
Var
[+] ₁
+ 15574.32
power factor of Load
cose - 20768-455
√3 VL IL
20768-45
0.8
1.32)
25957.20
Lag
NA
= (P+ja)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4e6c65b7-3196-400e-b607-889a090896bd%2F234de5c7-f0a2-414a-86bc-a8f6ff141213%2F7542ahn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:So line currents
IR = √3 | Jph | = 72.015 Amp L-36
Reactive
Sey = √5 $ phl = 42.05/-156.86 Amp
1/83. 14 Amp
IB
(P) Real (or) ture
w
complex power
power
P
power
72.05
=
* = √3 V₂ IL cosø
= √3 x 208 x 72.05 cos (36.86)
20768.455 watts.
N
= √3 Y₂ IL Sinds
(@=
25957. 20622 x0.6
15574.32
(20768.455
-36.86*
cost=
Cost =
Var
[+] ₁
+ 15574.32
power factor of Load
cose - 20768-455
√3 VL IL
20768-45
0.8
1.32)
25957.20
Lag
NA
= (P+ja)
Transcribed Image Text:1
208 V L
impedance
in
TFB
are
delta
'Iph phase
(RY)
line
Similarly
B
Since in
TER
Same
V₂
current
4+j3
= 208
4+√3
in
=
R
Iph (YB)
Vph
Iph (BR)
4+j³
connected system V₂ =
voltage voltage = phase voltage.
delta annected
Z₁, Z₂, Z3
=
Y
Vph Lon 20% L00
Loe
Zph
5/36-86
11.6 L-36-860
VL = Vph.
208 L-120
5 L36.96
241-
=
systém
4 +j3. =
-
A connection
|1₂| = √3 Iph (fx = 1y = 18)
FR
·156.86
208 4+120
5/36.86
=
5 /36.86° 0
Amp
Amp
41.6 L + 83.1
Астр
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