[TP] If you have two half-cells: Ag+ (1M) | Ag(s) with Eºred = 0.80 V and Cu²+(1M) | Cu(s) with Eºred = 0.34 V, which will be oxidized? =( Write the cell diagram that is spontaneous. E=E° 个 61% 1. Cu is oxidized: Cu(s) | Cu²+(1 M)|| Ag+(1 M) | Ag(s) 12% 2. Cu(s) | Cu²+(1 M)||Ag+ (1 M)|Ag(s) Ag is oxidized: Cu is oxidized: 15% 4. Ag is oxidized: 12% 3. Agts)|Ag (1 M) | | Cu² (1 M) | Cu(s) Ag(s) | Ag+ (1 M)||Cu²+(1 M) | Cu(s) E cell = Eox Ulu | (₂²4) + Ead (Ag+ / Ag) 27/₁1) ²0ut (0₂)
[TP] If you have two half-cells: Ag+ (1M) | Ag(s) with Eºred = 0.80 V and Cu²+(1M) | Cu(s) with Eºred = 0.34 V, which will be oxidized? =( Write the cell diagram that is spontaneous. E=E° 个 61% 1. Cu is oxidized: Cu(s) | Cu²+(1 M)|| Ag+(1 M) | Ag(s) 12% 2. Cu(s) | Cu²+(1 M)||Ag+ (1 M)|Ag(s) Ag is oxidized: Cu is oxidized: 15% 4. Ag is oxidized: 12% 3. Agts)|Ag (1 M) | | Cu² (1 M) | Cu(s) Ag(s) | Ag+ (1 M)||Cu²+(1 M) | Cu(s) E cell = Eox Ulu | (₂²4) + Ead (Ag+ / Ag) 27/₁1) ²0ut (0₂)
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter19: Principles Of Chemical Reactivity: Electron Transfer Reactions
Section: Chapter Questions
Problem 79GQ
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This is an image from my lecture. I am confused why Cu is being oxidized, in the formula why did Cu be converted to Eooxidation? When both values given were Eoreduction?
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