to 19.0 g/cm³ at the other. (a) The density as a function of distance for the rod is given by p= B + Cx, where B and C are constants. What are the values of B (in g/cm³) and C (in g/cm4)? B = C = g/cm3 9/cm4 (b) Finding the total mass of the rod requires integrating the density function over the entire length of the rod. The integral is written as follows. m = = p dv = pA dx = Jo Jallmaterial What is the total mass of the rod (in kg)? kg 3 16.0 cm (B+ Cx)(7.00 cm²) dx

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Chapter1: Physics And Measurement
Section: Chapter Questions
Problem 1.67AP: A rod extending between x = 0 and x = 14.0 cm has uniform cross-sectional area A = 9.00 cm2. Its...
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A thin rod extends from x = 0 to x = 16.0 cm. It has a cross-sectional area A = 7.00 cm², and its density increases uniformly in the positive x-direction from 3.50 g/cm³ at one endpoint
to 19.0 g/cm³ at the other.
(a) The density as a function of distance for the rod is given by p = B + Cx, where B and C are constants. What are the values of B (in g/cm³) and C (in g/cm+)?
g/cm³
g/cm4
B =
C =
(b) Finding the total mass of the rod requires integrating the density function over the entire length of the rod. The integral is written as follows.
- Sumaterial
Love
X
m =
p dv =
pA dx =
What is the total mass of the rod (in kg)?
kg
/0
*16.0 cm
(B+Cx) (7.00 cm²) dx
Transcribed Image Text:A thin rod extends from x = 0 to x = 16.0 cm. It has a cross-sectional area A = 7.00 cm², and its density increases uniformly in the positive x-direction from 3.50 g/cm³ at one endpoint to 19.0 g/cm³ at the other. (a) The density as a function of distance for the rod is given by p = B + Cx, where B and C are constants. What are the values of B (in g/cm³) and C (in g/cm+)? g/cm³ g/cm4 B = C = (b) Finding the total mass of the rod requires integrating the density function over the entire length of the rod. The integral is written as follows. - Sumaterial Love X m = p dv = pA dx = What is the total mass of the rod (in kg)? kg /0 *16.0 cm (B+Cx) (7.00 cm²) dx
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