tn charge? W (d) 21, A particle with charge +q is at the origin. A particle with Se charge -2q is at x = 2.00 m on the x axis. (a) For what finite to value (s) of x is the electric field zero? (b) For what finite value (s) of x is the electric potential zero? 30 bail ()

University Physics Volume 2
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Chapter5: Electric Charges And Fields
Section: Chapter Questions
Problem 52P: Suppose Earth and the Moon each carried a net negative charge Q . Approximate both bodies as point...
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I am having a hard time understanding why the solved answer on your site, for the following question, uses x-2 instead of x+2 for the -2q charge.  I attached my work for part A as well as where I am confused at. Aren't I just supposed to solve for x at this point? The - seems to be throwing me off. Any explanation you can offer would be appreciated!

tn
charge?
W (d)
21, A particle with charge +q is at the origin. A particle with
Se
charge -2q is at x = 2.00 m on the x axis. (a) For what finite
to
value (s) of x is the electric field zero? (b) For what finite
value (s) of x is the electric potential zero?
30
bail ()
Transcribed Image Text:tn charge? W (d) 21, A particle with charge +q is at the origin. A particle with Se charge -2q is at x = 2.00 m on the x axis. (a) For what finite to value (s) of x is the electric field zero? (b) For what finite value (s) of x is the electric potential zero? 30 bail ()
Expert Solution
Step 1

Given q1 = +q at originq1 = -2q distane between them is r = 2.0 m

From Coulomb's law, we know the electric field at a distance r form the point is given as

E = keqr2ke = 14πε = 9 ×109 Nm2/C2

And electric potential at some point due to several point charge is the sum of individual potential

V = iVi = keiqiri

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