This asset is similar across other asset replacement questions: An asset has a first cost of $70,000. In the first year the asset loses $20,000 n value, and then falls in value by orthorcaft fto
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- Caduceus Company is considering the purchase of a new piece of factory equipment that will cost $565,000 and will generate $135,000 per year for 5 years. Calculate the IRR for this piece of equipment. For further instructions on internal rate of return In Excel, see Appendix C.Answer the question. A challenger asset with a maximum useful life of 6 years has a first cost of $43,000 and an estimated annual operating cost of $6250. The market value is expected to decrease by $6450 each year for the next 6 years. If the MARR is 10% per year, fill in blanks below to correctly represent the equation for calculating the EUAC at the end of year 2. (HINT: skip $ and comma symbols) EUAC2 = 43,000 ( 10%, 2) + (43,000 - 6450*2) ( 10%,2)The data associated with operating and maintaining an asset are shown below. The company manager has already decided to keep the machine for 1 more year (i.e., until the end of year 1), but you have been asked to determine the cost of keeping it 1 more year after that. At an interest rate of 10% per year, estimate the AW of keeping the machine from year 1 to year 2. Operating Cost, $ per Year Market Value, $ 30,000 25,000 14,000 10,000 Year 0 1 2 3 -15,000 -15,000 -15,000
- Consider a machine that costs $1000 to purchase. The machine creates an annual operating expense of $500 at the end of first year, which is going to increase by $50 in each year thereafter. The salvage value of this machine is $200, independent of the usage period. Find the economic life of this machine under nominal MARR 25%, compounding annually. A 8. B. 6.An engineer with Haliburton calculated the AW values shown for retaining a presently owned machine additional years. A challenger has an economic service life of 7 years with AW = $-86,000 per year. Assuming all future costsremain as estimated for the analysis, (a) when should the company replace the defender and with what machine, and (b) when should the companypurchase the challenger? The MARR is 12% per year. Assume used machines like the one presently owned will always be available.A conveyor system costs $110,000 to install. The salvage value of the conveyor system decreases by $20,000 each year until its salvage value is $0, at which point it no longer decreases. The cost to operate and maintain the conveyor system the first year is $20,000; this cost increases by 7% per year. What is the optimal replacement interval and minimum EUAC for the conveyor system, assuming a MARR of 15% is used? Click here to access the TVM Factor Table Calculator. years ORI: EUAC*: $ Carry all interim calculations to 5 decimal places and then round your final answers to a whole number. The tolerance is ±10 for the EUAC*. eTextbook and Media Hint Assistance Used Construct an Excel® table that computes the EUAC for different values of n. This will help you to find EUAC*, from which you can deduce the optimal replacement interval.
- The AW method is to be used to select the better alternative of the two machines listed below, at 10% per year. Answer the below questions: Machine R Machine S First cost, $ 250,000 497,732 Annual operating cost, $ per year 40,000 50,000 Salvage value, $ Life, years 20,000 30,000 3. 5. The AW of Machine S=An equipment was purchased now at P10,000,000.00 prevailing interest rate is 10% per year. Solve the following cases capitalized cost: Answer no. 3 only Solve for case 1 if the projected maintenance cost will total P5,000,000.00 for 10 years. Use 10% as worth of money or interest rate. Solve for case 2 if the machine on item 1.1 is to be replaced every end of 10 years at 10% worth of money. Salvage cost is zero. Solve for case 3 using the above value on case 1 and 2 at 10%An equipment was purchased now at P10,000,000.00 prevailing interest rate is 10% per year. Solve the following cases capitalized cost: Solve for case 1 if the projected maintenance cost will total P5,000,000.00 for 10 years. Use 10% as worth of money or interest rate. Solve for case 2 if the machine on item 1.1 is to be replaced every end of 10 years at 10% worth of money. Salvage cost is zero. Solve for case 3 using the above value on case 1 and 2 at 10%
- $500,000 is invested in equipment having a salvage value equal to $500,000(0.80n) after n years of use. O&M costs equal $125,000 the first year and increase $15,000 per year. Based on a MARR of 10%, what are the optimum replacement interval and minimum EUAC?Show the complete solution. Do not used Excel. Use manual method/handwritten The maintenance costs of a new boiler are estimated as follows: P 600 per year for the first 3 years, P X at the 4th year, and P 1,800 per year starting at the 5th year up to the end of its 10 - year life. If the future value of all the maintenance is P 20,000, find the value of X. Money is 6% compounded annually.A commercial 3D printer is purchased for $350,000. The salvage value of the printer decreases by 30% each year that it is held. The cost to operate and maintain the machine the first year it is used is $14,000; these costs increase by $5,000 each year. What is the optimal replacement interval and minimum EUAC for the printer, assuming a MARR of 13% is used? Click here to access the TVM Factor Table Calculator. years ORI: EUAC*: $ Carry all interim calculations to 5 decimal places and then round your final answers to a whole number. The tolerance is ±5 for the EUAC*.