The volume of a sphere is increasing at a constant rate of 1827 cubic centimeters per second. At the instant when the radius of the sphere is 4 centimeters, what is the rate of change of the surface area of the sphere? The volume of a sphere can be found with the equation V = ³ and the surface 1 πρ area can be found with S = 4πr². Round your answer to three decimal places (if necessary).
The volume of a sphere is increasing at a constant rate of 1827 cubic centimeters per second. At the instant when the radius of the sphere is 4 centimeters, what is the rate of change of the surface area of the sphere? The volume of a sphere can be found with the equation V = ³ and the surface 1 πρ area can be found with S = 4πr². Round your answer to three decimal places (if necessary).
Mathematics For Machine Technology
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Chapter65: Achievement Review—section Six
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Problem 70AR: Compute the number of cubic centimeters of iron required for the cast-iron plate shown. The plate is...
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Transcribed Image Text:The volume of a sphere is increasing at a
constant rate of 1827 cubic centimeters per
second. At the instant when the radius of the
sphere is 4 centimeters, what is the rate of
change of the surface area of the sphere?
The volume of a sphere can be found with
the equation V = ³ and the surface
1
area can be found with S = 4πr². Round
your answer to three decimal places (if
necessary).
Answer:
Submit Answer
cm
2
sec
attempt 1 out of 2
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