The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasing as the resistor heats up. Use Ohm's Law, V = IR, to find how the current Iis changing at the moment when R = 398 Ω, I = 0.01 A, dV/dt = −0.04 V/s, and dR/dt = 0.05 Ω/s. (Round your answer to six decimal places.)A/s
The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasing as the resistor heats up. Use Ohm's Law, V = IR, to find how the current Iis changing at the moment when R = 398 Ω, I = 0.01 A, dV/dt = −0.04 V/s, and dR/dt = 0.05 Ω/s. (Round your answer to six decimal places.)A/s
Chapter3: Polynomial Functions
Section3.5: Mathematical Modeling And Variation
Problem 6ECP: The resistance of a copper wire carrying an electrical current is directly proportional to its...
Question
The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasing as the resistor heats up. Use Ohm's Law,
V = IR,
to find how the current Iis changing at the moment when
R = 398 Ω,
I = 0.01 A,
dV/dt = −0.04 V/s,
and
dR/dt = 0.05 Ω/s.
(Round your answer to six decimal places.)
A/s
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