The value of HLEN in an IP datagram is 7. How many option bytes are present?
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- Provide short answers to the following: How do you determine whether an IP address is a multicast address? What is the TTL field in the IP header used for? What is the maximum length of options bytes that can be carried in an IPv4 header? Why do we have to multiply the offset field of an IP datagram by eight to obtain the real offset for the first byte of the datagram?1. Suppose a TCP connection is transferring a file of 5550 bytes. The first byte is numbered 10001. What are the sequence numbers for each segment if each carries 500 bytes? How many Segments will be there ?2) In an IPV4 packet, the value of the HLEN field is 1100 in binary. How many bytes of options field is being carried by this packet? a) 28 byte b) 20 byte c) 8 byte d) 40 byte
- - Suppose a TCP message that contains 1024 bytes of data and 20 bytes of TCP header is passed to IP for delivery across two networks interconnected by a router (i.e., it travels from the source host to a router to the destination host). The first network has an MTU of 1024 bytes; the second has an MTU of 576 bytes. Each network's MTU gives the size of the largest IP datagram that can be carried in a link-layer frame. Give the sizes and offsets of the sequence of fragments delivered to the network layer at the destination host. Assume all IP headers are 20 bytes.7.Now I am sending the 3rd packets in a TCP link. Before this packets there are totally 200 bytes sent. Assume every packet is in equal size. What is the sequence number of this 3rd packet and what is the ACK number for this packet? 请输入答案In a TCP data packet, if the sequence number has the value 001111, ACK number has the value 010110 and the urgent pointer has the value 001100 assuming that URG flag is set. What is the last urgent byte in the data section of the packet? All numbers are in binary.
- Subject rcs511 In an IPv4 datagram, the M bit is 0, the value of HLEN is 10, the value of total length is 400 and the fragment offset value is 300. The position of the datagram, the sequence numbers of the first and the last bytes of the payload, respectively areAssume the maximum transmission unit (or MTU) of an IP packet on 100 Mbps Ethernet is set at 1500 bytes. Also, assume we are sending our file using IPv6 at the Network layer and UDP at the Transport layer. A typical IPv6 header consists of 40 bytes, a UDP header consists of 8 bytes. Answer the following three questions based on the information provided above. For all answers, enter a decimal integer value without formatting (no commas). 1. How many packets do we have to send in order to transfer a file of 24KB over 100 Mbps Ethernet? packets 2. How many bytes do we have to send at the network layer in order to transfer the above file entirely? bytes 3. How many bytes do we have to send at the data link layer in order to transfer the above file entirely? Assume that the Ethernet header is 14 bytes and the frame checksum is 4 bytes. bytesIf the TCP and IP headers contain no options, what will the MTU be given a MSS value of 492?
- P27. Host A and B are communicating over a TCP connection, and Host B has already received from A all bytes up through byte 126. Suppose Host A then sends two segments to Host B back-to-back. The first and second segments contain 80 and 40 bytes of data, respectively. In the first segment, the sequence number is 127, the source port number is 302, and the destination port number is 80. Host B sends an acknowledgment whenever it receives a segment from Host A. In the second segment sent from Host A to B, what are the sequence number, source port number, and destination port number? If the first segment arrives before the second segment, in the acknowledgment of the first arriving segment, what is the acknowledgment number, the source port number, and the destination port number? If the second segment arrives before the first segment, in the acknowledgment of the first arriving segment, what is the acknowledgment number? Suppose the two segments sent by A arrive in order at B.…Suppose the sequence number field on a TCP packet is 46005. The packet carries 102 bytes of (application-layer) data. The TCP header size on this packet is 20 bytes. (a) What is the sequence number of the last application byte contained in the packet above? (b) What is the value of the acknowledgment number field on the ACK that the receiver generates for the packet above? (c) Do you have sufficient information in this question to determine the value of the sequence number field of the ACK packet that the receiver generates for the packet above? If so, what is the sequence number? If not, why not? (d) If the size of the TCP header were larger (e.g., 24 bytes, due to additional TCP options), would your answers to parts (a)–(c) change? Why or why not?In a TCP connection, the initial sequence number at the client site is 2171. The client opens the connection, sends three segments, the second of which carries 1000 bytes of data, and closes the connection. What is the value of the sequence number in each of the following segments sent by the client? a. The SYN segment b. The data segment c. The FIN segment