The time spent on social media platforms per day by adults has a distribution with a mean of 125 minutes and a standard deviation of 16 minutes. A random sample of size 16 adults is selected from the population. Find the mean and standard error of the sample mean time spent on social media platforms per day.

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A: The question is about types of data Introduction : Qualitative data : If the value variable…

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A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

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A: Given : population proportion , p = 40% = 0.40

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A: Given information: A die is rolled one time.

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A: “Since you have asked multiple questions, we will solve the first question for you. If you want any…

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A: Since you have posted a question with multiple sub parts, we will provide the solution only to the…

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A:

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A: Given information: n1=7, n2=10s12=225, s22=118

Q: be

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A: given  data normal distributionμ = 1050σ = 218n = 50p ( x¯ > 1075) = ?

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A: Given information: A table for Heartatk is given.

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A:

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A: Solution

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A: analysis of variance can be used to test multiple means.

Q: difference between two population means - Independent

A: *Answer: Given data Population standard deviations σ1=0.94andσ2=1.09 sample sizes…

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A: given data normal distributionμ = 241σ = 17n= 10

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A: The objective is to interpret the 99% confidence interval in terms of the "level of confidence".  In…

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A: Given: Mean μ=1000 Standard deviation σ=105

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A: Since you have asked multiple question, we will solve the first question for you. If you want any…

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A: Given information: PA=0.34PB=0.19PA∩B=0.051

Q: V Σ(x − x)(y; - 5) Σ(-x)Σ(; - 5) V[n(Ex? η Σ. xiv. - Σ. x Συ - (Σ.x2] [n(Σ» - (Σ»]

A: Given information: r=∑xi-x¯yi-y¯∑xi-x¯2∑yi-y¯2=n∑xiyi-∑xi∑yin∑xi2-∑xi2n∑yi2-∑yi2

Q: ▸ Dashboard с YouTube MyOpenMath…

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Q: QUESTION 5 Let X, Y be joint Gaussian random variables with E[X]=0,E[Y] =0, Var[X] =2, Var[Y] =4 and…

A:

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A:

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A:

Q: Stat 243-007 Fall 2017 In each part of problems 1 and 2, (i) write the probability in terms of X or…

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A: given data  n = 100x¯ = 936 hourss = 87 hoursZ score  = 1.56lifespan of bulb (X) = ?

Q: Assume that male and female heights are both normally distributed with a male average of 69.1 inches…

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A: given data, normal distributionμ=1532σ=200n=50we have to find out the given probabilties.

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A: Given data: School 1 School 2 School 3 650 505 590 620 550 510 630 700 520 580 630 500…

Q: Population Proportion

A:

Q: How do you solve this problem using a TI-84 Plus calculator?

A: It is given that the hypothesized population proportion (p) is 1/2 =0.50.

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