The test statistic of z=−2.41 is obtained when testing the claim that p<0.79. a. Using a significance level of α=0.05, find the critical value(s). b. Should we reject H0 or should we fail to reject H0?
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- The test statistic of z = - 3.36 is obtained when testing the claim that p< 0.41. a. Using a significance level of a= 0.05, find the critical value(s). b. Should we reject Ho or should we fail to reject Ho?The test statistic of z= - 1.66 is obtained when testing the claim that p<0.71. a. Using a significance level of a = 0.01, find the critical value(s). b. Should we reject Họ or should we fail to reject Ho ?The test statistic of z = - 2.39 is obtained when testing the claim that p<0.12. a. Using a significance level of a = 0.10, find the critical value(s). b. Should we reject Ho or should we fail to reject H,?
- a. Report and interpret the P-value for Fisher's exact test with (i) Ha: 0 > 1 and (ii) Hạ: 0 # 1. Explain how the P-values are calculated. b. Find and interpret the mid P-value for Ha: 0 > 1. Summarize advantages and disadvantages of this type of P-value. Table 3.14 Data for Exercise 3.18 on Therapy for Cancer of Larynx Cancer Controlled Cancer Not Controlled Surgery Radiation therapy 21 15 23The test statistic of z=2.29 is obtained when testing the claim that p≠0.418. a. Find the P-value. Using a significance level of α=0.10, should we reject H0 or should we fail to reject H0? a. P-value=____(Round to three decimal places as needed.)Which of the following values results from the use of a statistical test? 1. The critical value 2. The obtained value 3. Type I error 4. Type II error
- If the test statistic for a right sided test is z = 1.71, then the p-value isSelect one: A.0.9573 B.0.9564 C.0.0436 D.0.0427The mean salary of federal government employees on the general schedule is $59,593. The average salary of 30 state employees who do the similar work is $ 58,800 with α =$1500. At the 0.01 level of significance, can it be concluded that state employees earn on average less than federal employees?Thomas is wanting to know if the amount of time students who got an A studied on their final last term is different than the typical 4 hours. To find out he surveys the students. His hypotheses are: H0:μ=4hr Ha:μ≠4hr He calcullates the average. His latest tesst statistic is 2.27, and his P-value is 0.0232. Using a significance level of α=5 Reject H0 μ is different than 4 hours. Accept Ha μ is not different than 4 hours. Fail to reject H0 μ is different than 4 hours. Accept Ha μ is different than 4 hours.
- produce a CROSSTAB for the variables SEX and FEFAM. Examine the relationship between these variables by testing both statistical significance and strength of association. Use chi-square for significance and choose the appropriate measures for strength of association (Phi, Cramer’s V, Lambda, or Gamma). Set alpha to .05. State the null and research hypotheses: H0: H1: What is the obtained chi-square value? What is the significance level (p-value) for the obtained chi-square? Should we reject or fail to reject the null hypothesis? Is there a statistically significant relationship between these variables? Which measure of association would be most appropriate for these variables? What is the value of the measure of association? Interpret your findings by explaining in full sentences whether there is a statistically significant relationship or not and the strength of the relationship. Also explain any patterns you see in the percentages:Use the calculator displays to the right to make a decision to reject or fail to reject the null hypothesis at a significance level of α = 0.01. Choose the correct answer below. O A. Since the P-value is less than a, reject the null hypothesis. OB. Since the P-value is greater than x, fail to reject the null hypothesis. OC. Since the P-value is less than a, fail to reject the null hypothesis. OD. Since the P-value is greater than a, reject the null hypothesis. ... Z-Test Z-Test Inpt: Data Statsu #50 Ho:50 6:5.75 X:48.75 n:35 H:Ho Ho Ho > Calculate Draw z = -1.2861043 p=0.19840666 x = 48.75 n = 35Only about 15% of all people can wiggle their ears. Is this percent different for millionaires? Of the 726 millionaires surveyed, 137 could wiggle their ears. What can be concluded at the 0.05 level of significance? H0: p = 0.15 Ha: p [ Select ] [">", "Not Equal To", "<"] 0.15 Test statistic: [ Select ] ["Z", "T"] p-Value = [ Select ] ["0.07", "0.007", "0.14", "0.004"] [ Select ] ["Fail To Reject Ho", "Reject Ho"] Conclusion: There is [ Select ] ["statistically significant", "insufficient"] evidence to make the conclusion that the population proportion of all millionaires who can wiggle their ears is not equal to 0.15. I NEED THE LAST THREE.