The test statistic of z=−2.31 is obtained when testing the claim that p=1/2. a. Using a significance level of α=0.05, find the critical value(s). b. Should we reject H0 or should we fail to reject H0?
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find the critical value(s).
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- The test statistic of z = - 1.73 is obtained when testing the claim that p = 1/2. a. Using a significance level of a = 0.05, find the critical value(s). b. Should we reject H, or should we fail to reject H,?The test statistic of z = - 2.39 is obtained when testing the claim that p<0.12. a. Using a significance level of a = 0.10, find the critical value(s). b. Should we reject Ho or should we fail to reject H,?The test statistic of z = -1.62 is obtained when testing the claim that p = 3/5. a. Using a significance level of α = 0.05, find the critical value(s). b. Should we reject Ho or should we fail to reject Ho?
- The test statistic of z = -2.13 is obtained when testing the claim that p< 0.43. a. Using a significance level of a= 0.10, find the critical value(s). b. Should we reject Ho or should we fail to reject Ho?The test statistic of z= -16.8 is obtained when testing the claim that p= 1/2 a. Using a significance level of α=0.01, find the critical value(s). b. Should we reject H0 or should we fail to reject H0?The test statistic of z=−2.15 is obtained when testing the claim that p=3/8. a. Using a significance level of α=0.01, find the critical value(s). b. Should we reject H0 or should we fail to reject H0?
- The test statistic ofz=−1.58 is obtained when testing the claim that p =3/5. a. Using a significance level of α= 0.05, find the critical value(s). b. Should we reject H0 or should we fail to reject H0?Select the correct answer below: We should reject the null hypothesis because t0<tα/2. So, at the 5% significance level, the data provide sufficient evidence to conclude that the average heights of soccer players is not equal to 76 inches. We should reject the null hypothesis because t0>−tα/2. So, at the 5% significance level, the data provide sufficient evidence to conclude that the average heights of soccer players is not equal to 76 inches. We should reject the null hypothesis because −tα/2<t0<tα/2. So, at the 5% significance level, the data do not provide sufficient evidence to conclude that the average heights of soccer players is not equal to 76 inches. We should not reject the null hypothesis because t0>−tα/2. So, at the 5% significance level, the data do not provide sufficient evidence to conclude that the average heights of soccer players is not equal to 76 inches. We should not reject the null hypothesis because…Thomas is wanting to know if the amount of time students who got an A studied on their final last term is different than the typical 4 hours. To find out he surveys the students. His hypotheses are: H0:μ=4hr Ha:μ≠4hr He calcullates the average. His latest tesst statistic is 2.27, and his P-value is 0.0232. Using a significance level of α=5 Reject H0 μ is different than 4 hours. Accept Ha μ is not different than 4 hours. Fail to reject H0 μ is different than 4 hours. Accept Ha μ is different than 4 hours.