The table STUDENT has the attributes STUDENT_ID, NAME, S_ID, and ADDR. The table SCHOOL has the attributes SCHOOL_ID, NAME, and STATE_CODE. Assume that there is a 1:N relation between SCHOOL and STUDENT where the common attributes are S_ID, and SCHOOL_ID. Which of the following creates a table that shows the STUDENT attributes and the corresponding SCHOOL attributes? a. SELECT * FROM STUDENT JOIN SCHOOL USING(SCHOOL_ID) b. SELECT * FROM STUDENT JOIN SCHOOL USING(S_ID) c. SELECT * FROM STUDENT NATURAL JOIN SCHOOL ON S_ID AND SCHOOL.SCHOOL_ID d. SELECT * FROM STUDENT JOIN SCHOOL ON STUDENT.S_ID = SCHOOL.SCHOOL_ID
The table STUDENT has the attributes STUDENT_ID, NAME, S_ID, and ADDR. The table SCHOOL has the attributes SCHOOL_ID, NAME, and STATE_CODE. Assume that there is a 1:N relation between SCHOOL and STUDENT where the common attributes are S_ID, and SCHOOL_ID. Which of the following creates a table that shows the STUDENT attributes and the corresponding SCHOOL attributes? a. SELECT * FROM STUDENT JOIN SCHOOL USING(SCHOOL_ID) b. SELECT * FROM STUDENT JOIN SCHOOL USING(S_ID) c. SELECT * FROM STUDENT NATURAL JOIN SCHOOL ON S_ID AND SCHOOL.SCHOOL_ID d. SELECT * FROM STUDENT JOIN SCHOOL ON STUDENT.S_ID = SCHOOL.SCHOOL_ID
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
The table STUDENT has the attributes STUDENT_ID, NAME, S_ID, and ADDR. The table SCHOOL has the attributes SCHOOL_ID, NAME, and STATE_CODE. Assume that there is a 1:N relation between SCHOOL and STUDENT where the common attributes are S_ID, and SCHOOL_ID. Which of the following creates a table that shows the STUDENT attributes and the corresponding SCHOOL attributes?
| a. |
SELECT * FROM STUDENT JOIN SCHOOL USING(SCHOOL_ID) |
|
| b. |
SELECT * FROM STUDENT JOIN SCHOOL USING(S_ID) |
|
| c. |
SELECT * FROM STUDENT NATURAL JOIN SCHOOL ON S_ID AND SCHOOL.SCHOOL_ID |
|
| d. |
SELECT * FROM STUDENT JOIN SCHOOL ON STUDENT.S_ID = SCHOOL.SCHOOL_ID |
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