The table below provides kinetic information when ADH is reacted with ethanol alone, NAD+ alone, and ethanol with NAD+ 1) Assuming Michaelis-Menten behavior, plot the data (substrate/cofactor concentration on x-axis vs. kinetic data on y-axis) for each experiment in ONE PLOT
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The table below provides kinetic information when ADH is reacted with ethanol alone, NAD+ alone, and ethanol with NAD+
1) Assuming Michaelis-Menten behavior, plot the data (substrate/cofactor concentration on x-axis vs. kinetic data on y-axis) for each experiment in ONE PLOT
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- Biochemistry: [S] (M) Vo (uM/ min) 2.5 x 10-6 28 4.0 X 10-6 40 1 X 10-5 2 x 10-5 4X 10-5 1 x 10-4 2 x 10-3 1 x 10-2 70 95 112 128 139 140 A) Estimate the values of Km and Vmax from the table (Without using graphs) B) With the table's help, what should be the values in order for an inhibitor that we will insert the system, will inhibit: 1)Competitive? 2)Noncompetitive? 3)Uncompetitive? 4) Irreversible?Siturul alORK ING )A mother brings her 251b child Into the ER with q very high fevero she has already ad ministered l2 4sp of Tylenol at home. She has brought the bottle with her and the label states: Acetamaino phere syrmp 325 mg / 5mLo Administer 10-15 mg /89 every 4 hrs as needed . How many milligrams oL Tylenot has she givern? Was this asafe dose to give the child?The concentration ofacetylcholine (a neurotransmitter) in a sample can be determined from the pH changes thataccompany its hydrolysis. When the sample is incubated with the enzymeacetylcholinesterase, acetylcholine is converted to choline and acetic acid, whichdissociates to yield acetate and a hydrogen ion: In a typical analysis, 15 mL of an aqueous solution containing an unknown amount ofacetylcholine had a pH of 7.65. When incubated with acetylcholinesterase, the pH of thesolution decreased to 6.87. Assuming there was no buffer in the assay mixture, determinethe number of moles of acetylcholine in the 15 mL sample.
- 140 120 Super- critical A 100 fluid CO,(s) Co,(1) 80 Critical point 30.98°C, 60 72.79 atm 40 В 20 CO>(g) Triple point - 56.57°C, 5.11 atm -80 -60 -40 - 20 20 40 Temperature (C) Above is the phase diagram of CO2. What is the slope (in atm K1) of the line BC at 0°C? The Enthalpy of vaporization of CO2 is 15.326 kJ mol1. The density of CO2(1) and CO2(g) are 927 g/L and 1.977g/L, respectively. Pressure (atm)The energy of activation for the reaction 2 HI – H2 + I2 is 180. kJ•mol-1 at 544 K. Calculate the rate constant using the equation k = Ae-EalRT. The collision diameter for HI is 3.5×10-8 cm. Assume that the pressure is 1.00 atm. 4.0 4.510e-27 X M-1.s-1In cation exchange chromatography, positively charged counter-ions will be bound to the stationary phase. O True O False
- A glucose solution is supplied in a repeated fed batch culture. The following parameters have been measured at t=2.5 hours; the system was under a quasi-steady state at this time. V = 1.0L, F = 0.22L/hr, S_0 = 98g/L, mu_m = 0.31/hr, K_s = 0.14 g-glucose/L, YM_X/S = 0.48 g-cells/g-glucose, Xt_0 = 33g (1) Calculate the value of V0 and S. (2) Calculate the value of Xt for t = 2.5hrs.SHOW COMPLETE SOLUTION 1. An electrochemical cell consist of 0.2715 Ibs of MnO2, and 0.2524 Ibs of PbO2. A current flow through a 1.1 ohm resistor of electrochemical cell for 45 mins. The reaction takes place at 400k and the total volume of the solution is 504.9 cm^3. Use the standard reduction cell potential table for MnO2 and PbO2: concentration of Mn2+ (2.81 M) and PbO2 (0.95 M) Cell Potential E=0.48 V current when it passes through a 1.1 ohm resistor = 0.44 ampere Determine the following: a. quantity of electricity/charge, Q b. Energy consumed in Joules c. Power in KilowattsAcute phase reactants, for example, increase the ESR in what way?
- The protein calcineurin binds to the protein calmodulin with an association rate of 8.9 × 103 M−1 s −1 and an overall dissociation constant, Kd, of 10 nM. Calculate the dissociation rate, kd , including appropriate units.Calculate, or make a best estimate of, the unknown factors in the situations listed in Table 1. Table 1. Data for problem 1. To find Data (i) Ek [K+]out = 4 mM; [K+]in = 130 mM (ii) [Cl-]in [Cl-]out = 570 mM; ECl = -65 mV (iii) ECl [Cl-]out = 150 mM; [Cl-]in = 8 mM; in a mammal (iv) [Na+]in Overshoot of action potential = +35 mV; saline [Na+] = 112 mM (v) [K+]in Blood [K+] = 3.2 mM; undershoot of action potential = -87 mV (vi) ECa [Ca2+]out = 5.6 mM; free [Ca2+]in = 0.8 mM (vii) [K+]out [K+]in = 350 mM; Ek = -82 mVExample The standard half electrode potential for Fe²+ vs SHE is 0.77 V. What is the value of Ee at T = 298K when: [Fe³+] = 0.2 mol l-1 [Fe2+] = 0.05 mol 1-1