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The system of first order differential equations y₁ = -4y₁ + 5y2 + 1 32 = 5y1 - 4y2 +1 where yı(0) = 0, y2 (0) = 0 has solution y₁ (t)= 4e³t y2(t) = -7e³t

The system of first order differential equations y₁ = -4y₁ + 5y2 + 1 32 = 5y1 - 4y2 +1 where yı(0) = 0, y2 (0) = 0 has solution y₁ (t)= 4e³t y2(t) = -7e³t

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.1: Solutions Of Elementary And Separable Differential Equations
Problem 10E
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Entered 4*[e^(3*t)] -7*[e^(3*t)] At least one of the answers above is NOT correct. has solution yı(t)=4e³t y₂(t) = -7e³t The system of first order differential equations y'₁ = −4y1 + 5y2 + 1 y2 = 5y1 - 4y2 +1 where y₁ (0) = 0, y₂ (0) = 0 Answer Preview 4e³t -7e³t Result incorrect incorrect
Transcribed Image Text:Entered 4*[e^(3*t)] -7*[e^(3*t)] At least one of the answers above is NOT correct. has solution yı(t)=4e³t y₂(t) = -7e³t The system of first order differential equations y'₁ = −4y1 + 5y2 + 1 y2 = 5y1 - 4y2 +1 where y₁ (0) = 0, y₂ (0) = 0 Answer Preview 4e³t -7e³t Result incorrect incorrect
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