The substance to be analyzed - is white, highly soluble in water salt. Interaction with water solution of sodium hydroxide leads to formation of white precipitate, soluble in reagent surplus. Addition to the substance solution of barium chloride leads to appearance of white precipitate (insoluble in hydrochloric acid). Spot assay (drop reaction, filter paper test) with alizarin gives red spot. What kind of salt is this? Al2(SO4)3 MnCl2 ZNSO4 Mn(NO3)2

The substance to be analyzed - is white, highly soluble in water salt. Interaction with water solution of sodium hydroxide leads to formation of white precipitate, soluble in reagent surplus. Addition to the substance solution of barium chloride leads to appearance of white precipitate (insoluble in hydrochloric acid). Spot assay (drop reaction, filter paper test) with alizarin gives red spot. What kind of salt is this? Al2(SO4)3 MnCl2 ZNSO4 Mn(NO3)2

Organic Chemistry

8th Edition

ISBN:9781305580350

Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Chapter4: Acids And Bases

Section: Chapter Questions

Problem 4.43AP

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The substance to be analyzed – is white, highly soluble in water salt. Interaction with water solution of sodium hydroxide leads to formation of white precipitate, soluble in reagent surplus. Addition to the substance solution of barium chloride leads to appearance of white precipitate (insoluble in hydrochloric acid). Spot assay (drop reaction, filter paper test) with alizarin gives red spot. What kind of salt is this? Al2(SO4)3 MnCl, ZNSO4 Mn(NO3)2
A sample is known to contain about 20% soda ash. What sample size should be taken for analysis, if it is to be dissolved into a 50 mL volumetric flask, with 10 mL aliquots analyzed, if it is desired that the analysis consume a total of 40 mL 0.10 M HCl with 10 mL of 0.10 M NaOH used in the back-titration, after boiling.
Which of the following conditions would lead to an increase in the relative supersaturation of a solution during precipitation gravimetry? a. decrease in temperature b. slow addition of precipitating agent c. precipitation from a hot solution d. vigorous stirring
The substance to be analyzed – is white, highly soluble in water salt. Flame coloration test gives carmine red color. Interaction with concentrated sulfuric acid leads to evolving of gas with pungent odour. Interaction with weak sulfuric acid solution leads to white precipitate formation. Interaction with water solution of silver nitrate leads to formation of white curdy precipitate, which soluble in saturated ammonium carbonate solution. What kind of substance is this? Explain you answer, provide chemical equations . 1.
The graphic below shows the general procedure for titrating the saturated solution of magnesium hydroxide with hydrochloric acid. Select all of the true statements from the choices below. 1. Obtain a saturated solution of magnesium hydroxide. 0 2. Transfer 30.0 mL to an Erlenmeyer flask using a volumetric pipet. Add phenolphthalein. 3. Titrate to a colorless endpoint using 0.0020 M hydrochloric acid. It is important that the aliquot drawn in step 2 does not contain undissolved magnesium hydroxide solid. For titrations of the saturated solutions at elevated temperatures, the solution must be held at high temperature for the duration of the titration. Hydrochloric acid is the analyte in this titration. The volume of liquid in the buret should be read before and after the titration. At the endpoint of the titration, the solution will turn from colorless to pink.
TRUE OR FALSE 1. Sodium arsenite is formed due to the solubility property of arsenic trioxide in sodium hydroxide. 2. The permanganate method is always carried out in a highly acidic medium. 3. The color of permanganate solution renders impossible accurate readings at the lower meniscus. 4. Sodium bicarbonate in the standardization of iodine solution acts as a buffer. 5. Sulfuric acid in permanganate titration prevents the formation of reduction products.
true or false 1.,Carbonic acid, as a contaminant in the assay of sodium bicarbonate, may render the end point to be yellow. 2,.To have a balanced equation in the assay of sodium bicarbonate, the titrant should have a coefficient of one and the sulfate salt of sodium produced should have a coefficient of three. 3.When a weak alkali is titrated with strong acid, the indicator used is methyl red.4 4.Sodium bicarbonate is considered as the primary standard in its own assay. 5.When a strong alkali is titrated with a strong acid, phenolphthalein may be used.
Standard solution : 0.201 grams of acetylsalicylic acid was combined with 10 mL of 0.5 M NaOH, then transfered to a 100 mL flask and filled the rest of the way with water Then 0.500 mLs of the standard solution was transfered to a 10.00 mL flask and diluted to the 10 mL mark with 0.02 M of buffered iron chloride. This step was repeated using 0.400, 0.300, 0.200, 0.100 mLs of the standard solution Questions: A.) determine the concentration of the acetylsalicylic acid in the 100.00 mL volumetric flask containing the solution from which the standards were made. B.)determine the concentration of the acetylsalicylic acid in each of the 10.00 mL calibration solutions. I only need the work for 0.400 mLs C.)Make a scatter plot (on the computer again) of absorbance versus concentration for the calibration samples. On the plot, add a linear trendline, and display the equation and the R2 value on the chart. Take your time to label the axes
Three drops of the phenolphthalein chemical indicator should be added to the acidic analyte sample (KHP or citric acid) before every titration. You will then carefully add the base to the analyte until the solution turns O a. from clear to a very pale pink color. O b. from a pale pink color to totally clear. O. from a dark pink color to totally clear. O d. from clear to a very dark pink color.
Which among the statements to promote large precipitates is INCORRECT? Having a dilute solution will keep supersaturation ratio small. Temperature affects particle size during crystal growth. The order of addition of the precipitating reagents may affect induction period. It is better to have a faster rate of nucleation than the rate of crystal growth.
If the size of the precipitate is smaller than pores of the filter paper, the paper cannot retain the precipitate. Give two separation methods that may overcome this difficulty.
Why homogenously formed precipitates are better suited for analysis than a precipitate formed by direct addition of a precipitating agent?